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3 years ago

Which equation is written in slope-intercept form?

Mathematics

2 answers:

Marysya12 [62]3 years ago

7 0

Answer:

A) y = 3x - 2

Step-by-step explanation:

slope-intercept form is represented by y=mx+b

your answer choices look like this

A) y = 3x -2

B) x = 1/2y + 8

C) 2x + 5y = 12

D) 3y = 8x - 5

right away, you can eliminate B & C, since they just don't represent the formula correctly.

D is your trick answer choice. at first glance, it looks right, however, the 'y' is not isolated, which is a key interpretation of the formula.

therefore, from process of elimination, A is right because is correctly represents the formula of slope-intercept form.

i hope this helps!

stay safe!

Ivanshal [37]3 years ago

5 0

Answer:

y = 3x - 2

Step-by-step explanation:

See Image for all the rest of the equation forms

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On one day a Plumber Joe earned $80 on a plumbing job. Out of his earnings he spent $6.85 on tea and snacks, $5.50 on food and $

In-s [12.5K]

Answer:

Joe saved 68.25

Step-by-step explanation:

Subtract 6.85 from 80, you get 73.15

Subtract 5.50 from 73.15 and you get 67.65.

Subtract 21.40 from 67.65 and you get 46.25.

Add 22 to that amount, you get 68.25.

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3 years ago

Find the value of x in the triangle below

Tom [10]

Answer:

6.76

Step-by-step explanation:

applying pythogorem theorem

a^2+b^2=c^2

5^2+b^2=13^2

25+b^2=169

b^2=169/25

b^2=6.76^2

b=6.76

3 0

3 years ago

The material used to make a storage box costs $1.25 per square foot. The boxes have the same volume, so how much does a company

riadik2000 [5.3K]

Answer: A company saves $134.38 by choosing to make 50 of Box 2 instead of Box 1

Step-by-step explanation:

Hi, to answer this question we have to calculate the surface area of both boxes.

Surface area (A) = 2wl + 2lh + 2hw,

Where w is width, l is length , and h is height.

Box 1 = A = 2(6x20) + 2( 20x4) + 2 (4 x 6) =2 (120)+ 2 (80)+ 2(24) =448 in2
Box 2 = A = 2 (4x15)+ 2(15x8)+ 2(8x4) = 2(60)+2(120)+2(32)=424 in2

Since 1 inch = 0.0833333 foot

Box 1 = 448 in2 x 0,0833333 =37.34 ft2
Box 2= 424 in2 x 0,0833333 =35.19 ft2

Since the material used to make a storage box costs $1.25 per square foot.

Box 1 =37.34 ft2 x1.25 = $ 46.675
Box 2= 35.19 ft2 x 1.25 =$43.98

Since 50 of each are made:

Box 1 = $ 46.675 x50 =2,333.750
Box 2= $43.98 x50 =2,199.37

Subtracting both costs:

2,333.750(1) - 2,199.37(2) = $134.38

6 0

3 years ago

5) In a certain supermarket, a sample of 60 customers who used a self-service checkout lane averaged 5.2 minutes of checkout tim

Ne4ueva [31]

Answer:

$\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643$

$S_p=2.940$

$t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751$

$df=60+72-2=130$

$p_v =P(t_{130}$

Assuming a significance level of $\alpha=0.05$ we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

Step-by-step explanation:

Data given

Our notation on this case :

$n_1 =60$ represent the sample size for people who used a self service

$n_2 =72$ represent the sample size for people who used a cashier

$\bar X_1 =5.2$ represent the sample mean for people who used a self service

$\bar X_2 =6.1$ represent the sample mean people who used a cashier

$s_1=3.1$ represent the sample standard deviation for people who used a self service

$s_2=2.8$ represent the sample standard deviation for people who used a cashier

Assumptions

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

The statistic is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

And t follows a t distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

System of hypothesis

Null hypothesis: $\mu_1 \geq \mu_2$

Alternative hypothesis: $\mu_1 < \mu_2$

This system is equivalent to:

Null hypothesis: $\mu_1 - \mu_2 \geq 0$

Alternative hypothesis: $\mu_1 -\mu_2 < 0$

We can find the pooled variance:

$\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643$

And the deviation would be just the square root of the variance:

$S_p=2.940$

The statistic is given by:

$t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751$

The degrees of freedom are given by:

$df=60+72-2=130$

And now we can calculate the p value with:

$p_v =P(t_{130}$

5 0

3 years ago

Question 3

choli [55]

Answer:

((19)(49)/98)

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers