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ivolga24 [154]
2 years ago
12

Graph the line y = -2x - 2

Mathematics
1 answer:
Daniel [21]2 years ago
8 0

Answer:

-2x-2

For a line equation for the form of y = mx +b, the slope is m

m= -2

The function has no undefined points nor domain

constraints. There fore, the domain is

domain: -∞<x<∞

The range of polynomial with odd degrees is all the real numbers

range: -∞<f(x)<∞

Step-by-step explanation:

graph is inserted

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The length of a rectangle is 3yd longer than its width. If the perimeter of the rectangle is 50yd, find it’s length and width
bazaltina [42]

Answer:

3(15)

Step-by-step explanation:


3 0
3 years ago
Find the length of l on the curve r(t)=5cos(3t)i-5sin(3t)j+3tk over the interval [3,7]
stealth61 [152]
\mathbf r(t)=5\cos3t\,\mathbf i-5\sin3t\,\mathbf j+3t\,\mathbf k
\mathrm d\mathbf r(t)=\mathbf r'(t)\,\mathrm dt=(-15\sin3t\,\mathbf i-15\cos3t\,\mathbf j+3\,\mathbf k)\,\mathrm dt

\displaystyle\int_C\mathrm d\mathbf r(t)=\int_{t=3}^{t=7}\|\mathbf r'(t)\,\mathrm dt\|=\int_{t=3}^{t=7}\sqrt{225\sin^23t+225\cos^23t+9}\,\mathrm dt
=\displaystyle3\sqrt{26}\int_{t=3}^{t=7}\mathrm dt
=12\sqrt{26}
4 0
4 years ago
Find an equation of the line passing through the given points. Write the equation in the function notation.
Mrrafil [7]
First you need to find the slope of the line using the given coordinates of the two points.
The slope of the line = (1-4)/(4-3) = -3
Then you choose one pair of the coordinates given, either (3,4) or (4,1) , up to you, to find the equation of the line.
If you choose (3,4)
Then
(y-4)/(x-3) = -3
(y-4) = -3x+9
y = -3x+13

If you choose (4,1),
Then
(y-1)/(x-4) = -3
y-1 = -3x+12
y = -3x+13

So, F(x)=-3x+13
3 0
3 years ago
Read 2 more answers
Evaluate 2a - 7 when a=3
Eddi Din [679]

Answer:

-1

Step-by-step explanation:

Just substitute your variable in:

(2)(3)-7

Simplify:

2*3=6

6-7=-1

-1 is your answer.

-Stay golden :)

7 0
3 years ago
The engine torque y (in foot-pounds) of one model of car is given by y=−3.75x2+23.2x+38.8, where x is the speed (in thousands of
Stels [109]

Answer:

Step-by-step explanation:

If the engine torque y (in foot-pounds) of one model of car is given by y=−3.75x^2+23.2x+38.8

The engine speed is at maximum if dy/dx = 0

dy/dx = -2(3.75)x+23.2

dy/dx = -7.5x + 23.2

since dy/dx = 0

0 =  -7.5x + 23.2

7.5x = 23.2

x = 23.2/7.5

x = 3.093

Hence the maximum torque is 3.09 rev/min

8 0
3 years ago
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