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Artyom0805 [142]
2 years ago
10

Please answer, much appreciated!!!!!

Mathematics
1 answer:
Anestetic [448]2 years ago
6 0

Answer:

i don't understand your question

Step-by-step explanation:

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DO NOT PRANK!! I NEED HELP PLS (will give brainly)
Nitella [24]

Answer:

b

Step-by-step explanation:

hiiii

3 0
3 years ago
Read 2 more answers
Is the relationship shown by the data linear? How can you tell if it is or is not? If so, model the data with an equation.
yuradex [85]

Hello from MrBillDoesMath!

Answer:    The relationship is linear. The equation is y = 2x + 19

Discussion:

When x changes from -7 to -5 ( and increment of of +2),  y changes from 5 to 9 ( an increment of +4). When x changes from 5 to -3 (an increment of +2) , y changes from 9 to 13 (an increment of +4)... and so on.....

So far, when x changes by 2, y changes by 4.  This means the data falls on a line (so is linear). In fact,

(change in y) /  (change in x) = 4/2 = 2 =  slope of line.

so  y = 2x + b. As the line passes through the point ( -7, 5)

5 = 2 (-7) + b    or

5 = -14 + b       or ( adding 14 to both sides)

5 + 14 = 19  = b.

Hence the equitation the line is  y = 2x + 19

Thank you,

MrB

6 0
3 years ago
A study of commuting times reports the travel times to work of a random sample of 20 employed adults in New York State. The mean
Elodia [21]

Answer:

The standard error of the mean = 5.14 mins

Step-by-step explanation:

Number of random sample (n) = 20

Mean(X) = 31.25 mins

Standard deviation (α) = 23.7 mins

Standard error of mean =

standard deviation / √sample size

= 23.7/√20

= 23.7/4.4721

= 5.14 mins

5 0
4 years ago
1
Annette [7]

Answer:

c

Step-by-step explanation: If you do the math you can clearly see and I got the answer correct.

7 0
3 years ago
In a survey sample of 83 respondents, the mean number of hours worked per week is 39.04, with a standard deviation of 11.51. Cal
soldier1979 [14.2K]

Given that,

Sample size= 83

Mean number= 39.04

Standard deviation= 11.51

We know the critical t-value for  95% confidence interval which is equal to 1.989.

We also know the formula for confidence interval,

CI=( mean number - critical t-value*standard deviation/(sample size)^(1/2), mean number + critical t-value*standard deviation/(sample size)^(1/2))

So, we have

CI= (39.04 - 1.989*11.51/83^(1/2), 39.04 + 1.989*11.51/83^(1/2)

CI= (39.04 - 2.513,39.04 + 2.513)

CI= (36.527,41.553)

Therefore, 95% confidence interval for these data is (36.527,41.553), and this result interpret that the true value for this survey sample lie in the interval (36.527,41.553).

8 0
3 years ago
Read 2 more answers
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