Someone, please help me quick!!

leslie decides to join a gym she must pay a monthly fee plus a one-time fee to open a membership this situation can be modeled b

goldfiish [28.3K]

"55x" shows that she has to pay $55 a month and the "+80" is a one time fee to open a membership

7 0

3 years ago

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25.(01.05)

yKpoI14uk [10]

105 but I need 20 characters to

8 0

3 years ago

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If James make $7 per hour and Priya makes 20% more than James and Samantha makes 5% less than Priya how much does Samantha make

mixas84 [53]

Samantha makes $7.98 per hour

4 0

3 years ago

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A food store makes a 11–pound mixture of peanuts, almonds, and raisins. The cost of peanuts is $1.50 per pound, almonds cost $3.

Anastaziya [24]

Answer:

C) 6 lbs peanuts, 3 lbs almonds, 2 lbs raisins

Step-by-step explanation:

Your goal is to find out how many of each item will equate to 21 dollars. Your function is as follows:

1.5x+3y+1.5z=21

Where x, y, z are peanuts, almonds, raisins respectively (in that order). 21 is the total cost of the mixture.

All you have to do is start plugging in the variables given in the answer choices.

A) Peanuts (x) = 3, Almonds (y) = 6, Raisins (z) = 2

Everywhere you see x,y,z, you replace with their value.

$1.5x+3y+1.5z=21\\1.5(3)+3(6)+1.5(2)=21\\4.5+12+3=21\\\\19.5 \neq 21$

A doesn't equal 21. On to the next one.

B) Peanuts (x) = 8, Almonds (y) = 6, Raisins (z) = 2

Everywhere you see x,y,z, you replace with their value.

$1.5x+3y+1.5z=21\\1.5(8)+3(1)+1.5(2)=21\\12+3+3=21\\\\18 \neq 21$

B also doesn't equal 21. On to the next one...

C) Peanuts (x) = 6, Almonds (y) = 3, Raisins (z) = 2

Everywhere you see x,y,z you replace with their value.

$1.5x+3y+1.5z=21\\1.5(6)+3(3)+1.5(2)=21\\9+9+3=21\\\\\\21 = 21$

Both sides of the equation equal 21 which means C is our answer.

7 0

3 years ago

Find area of the shaded region.

Monica [59]

Answer:

The area of the shaded region is about 38.1 square centimeters.

Step-by-step explanation:

We want to find the area of the shaded region.

To do so, we can first find the area of the sector and then subtract the area of the triangle from the sector.

The given circle has a radius of 6 cm.

And the given sector has a central angle of 150°.

The area for a sector is given by the formula:

$\displaystyle A=\pi r^2\cdot \frac{\theta}{360^\circ}$

In this case, r = 6 and θ = 150°. Hence, the area of the sector is:

$\displaystyle \begin{aligned}A&=\pi(6)^2\cdot \frac{150}{360}\\ &=36\pi\cdot \frac{5}{12}\\&=3\pi \cdot 5\\&=15\pi \text{ cm}^2\end{aligned}$

Now, we can find the area of the triangle. We can use an alternative formula:

$\displaystyle A=\frac{1}{2}ab\sin(C)$

Where a and b are the side lengths, and C is the angle between them.

Both side lengths of the triangle are the radii of the circle. So, both side lengths are 6.

And the angle C is 150°. Hence, the area of the triangle is:

$\displaystyle A=\frac{1}{2}(6)(6)\sin(150)=18\sin(150)$

The area of the shaded region is equivalent to the sector minus the triangle:

$A_{\text{shaded}}=A_{\text{sector}}-A_{\text{triangle}}$

Therefore:

$A_{\text{shaded}}=15\pi -18\sin(150)$

Use a calculator:

$A_{\text{shaded}}=38.1238...\approx 38.1\text{ cm}^2$

The area of the shaded region is about 38.1 square centimeters.

6 0

3 years ago