The two answers are -4 and 4, because 0-4 is -4 and 0+4 is 4. Hope this helps
Answer:
$3098.93
Step-by-step explanation:
We can use the formula for compound growth to solve this. The formula is:
Where
F is the future value (the value at end of 14 years, our answer)
P is the initial amount invested ($1250)
r is the interest rate, in decimal (6.7% is 0.067)
t is the time in years (14, in our case)
<em>Plugging in all the information</em> we have:
The account will accrue $3098.93 after 14 years.
f(x) = 2x - 1
To obtain a function we require values of x for x = 3, 4, 5 , 6, .....
The output appears to increase in steps of 2
3 → 5
4 → 7
5 → 9
6 → 11
Looking at the consecutive values of y we should see that these are twice the corresponding value of x subtract 1
f(x) = 2x - 1 ← is a possible function
checking the values for x in the input
f(3) =(2 × 3 ) - 1 = 5
f(4) = (2 × 4 ) - 1 = 7
f(6) = (2 × 6 ) - 1 = 11
f(11) = (2 × 11 ) - 1 = 21
AFC = FC / Quantity printed
<span>So given she prints 1,000 posters: AFC = 250.00/1000 = $0.25 </span>
<span>Given she prints 2,000 posters: AFC = 250.00/2000 = $0.125 </span>
<span>Given she prints 10,000 posters: AFC = 250.00/2000 = $0.025 </span>
<span>ATC = TC / Quantity printed </span>
<span>where TC = FC + Variable C * Quantity printed </span>
<span>If she prints 1000: TC = 250 + 2000*1000 = 2,000,250 </span>
<span>ATC = 2,000,250/1000 = 2000.25 </span>
<span>If she prints 2000: TC = 250 + 1600*2000 = 3,200,250 </span>
<span>ATC = 3,200,250/2000 = 1600.125 </span>
<span>If she prints 10000: TC = 250 + 1600*2000 + 1000*8000 ($1000 for each additional poster after 2000) = 11,200,250 </span>
<span>ATC = 11,200,250/10000 = 1120.025</span>
Answer:
$199
Step-by-step explanation:
I = Prt
I = (1990)(0.05)(2)
I = 199
