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QveST [7]
2 years ago
10

What’s the answer to 10(x-2)-3 (x+3)

Mathematics
1 answer:
Svetlanka [38]2 years ago
5 0

Answer:7x-29

Step-by-step explanation: simplify and open the brackets.remember that a letter and a number cannot be sumed up but can my multipled together

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Va rog mult sa ma ajutati ,imi trebuie neaparat . plz
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amenda. de ce ai nevoie?

Step-by-step explanation:

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What is f and g answers
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F.
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Please could I have some Help :)
Ann [662]
The answer is 414.69023
6 0
3 years ago
Read 2 more answers
The legs of an isosceles right triangle are 5 inches long. What is the length of the hypotenuse of the triangle to the nearest i
In-s [12.5K]
The legs are 5 inches long.

Use the Pythagorean theorem:
5^2+5^2=c^2 \\
25+25=c^2 \\
50=c^2 \\
c=\sqrt{50} \\
c=\sqrt{25 \times 2} \\
c=5 \sqrt{2} \\
c \approx 7

The length of the hypotenuse of the triangle is approximately 7 inches long.
6 0
3 years ago
Read 2 more answers
Please Help. I really don’t get this concept, if you could explain it in detail it would be very appreciated
Dafna11 [192]
<h3>Answer: 24/25</h3>

=================================================

Explanation:

Sine is given to be negative, and so is tangent. This only happens in quadrant Q4

Recall that y = sin(theta), so if sin(theta) < 0, then we're below the x axis.

If tan(theta) < 0, then this means cos(theta) > 0

So we have y < 0 and x > 0 which places the angle somewhere in Q4.

--------------------------

Draw a right triangle as shown below in the attached image. We have AC = 25 and BC = 7. Use the pythagorean theorem to find that AB = 24

So this is what your steps may look like

a^2+b^2 = c^2

7^2+b^2 = 25^2

b^2+49 = 625

b^2 = 625-49

b^2 = 576

b = sqrt(576)

b = 24

So because AB = 24, we know that the cosine of the angle is adjacent/hypotenuse = 24/25

---------------------------

As an alternative, you could use the trig identity

sin^2(x) + cos^2(x) = 1

and plug in the given value of sine to solve for cosine. The cosine value result will be positive since we're in Q4.

So,

sin^2(x) + cos^2(x) = 1

(-7/25)^2 + cos^2(x) = 1

(49/625) + cos^2(x) = 1

cos^2(x) = 1 - (49/625)

cos^2(x) = (625/625) - (49/625)

cos^2(x) = (625-49)/625

cos^2(x) = 576/625

cos(x) = sqrt(576/625)

cos(x) = sqrt(576)/sqrt(625)

cos(x) = 24/25

This is effectively a rephrasing of the previous section since the pythagorean trig identity is more or less the pythagorean theorem (just in a trig form)

6 0
3 years ago
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