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2 years ago

What is the y-intercept when a line has a slope of 3 and passes through the point (2, 7)?

Mathematics

1 answer:

dybincka [34]2 years ago

4 0

Answer:

The y-intercept is (0,1)

Step-by-step explanation:

So, first you need to find the equation! Point slope form is (y-y1)=m(x-x1).

Plug the numbers in and you get (y-7)=3(x-2). Now, the y intercept is where x=0, so plug in zero for x.

y-7=3(0-2)

y-7=3(-2)

y-7= -6.

-6+7= 1, so y=1

The ordered pair is then (0,1). Hope this was useful :)

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Tony had an equal number of cranberry bars and walnut bars. He gave away 66 cranberry bars, he then had 4 times as many walnut b

Korolek [52]

Answer:

W=88

Step-by-step explanation:

4*(c-66)=c

4c-66*4=c

3c=66*4

c=22*4

c=88

w=88

4 0

2 years ago

Read 2 more answers

A manufacturer of televisions subjects the equipment to a comprehensive testing process for all essential functions before the t

Scorpion4ik [409]

Answer:

The probability is $P(X \le 9) =0.9138$

Step-by-step explanation:

From the question we are told that

The probability of the television passing the test is p = 0.95

The sample size is n = 10

Generally the comprehensive testing process for all essential functions follows a binomial distribution

i.e

$X \~ \ \ \ B(n , p)$

and the probability distribution function for binomial distribution is

$P(X = x) = ^{n}C_x * p^x * (1- p)^{n-x}$

Here C stands for combination hence we are going to be making use of the combination function in our calculators

Generally the probability that at least 9 pass the test is mathematically represented as

$P(X \le 9) = P(X = 9) + P(X = 10 )$

=> $P(X \le 9) = [^{10}C_9 * (0.95)^9 * (1- 0.95)^{10-9}]+ [^{10}C_{10} * {0.95}^{10} * (1- 0.95)^{10-10}]$

=> $P(X \le 9) = [10 * 0.6302 * 0.05 ]+ [1 *0.5987 * 1 ]$

=> $P(X \le 9) =0.9138$

8 0

2 years ago

Simplify (-2)(-3)^2-2(2 - 5) <br><br>39 -12 -24

daser333 [38]

Answer:

-12

Step-by-step explanation:

(-2)(-3)^2-2(2-5). Original

-2(9)-2(2-5) Distribute Exponents

-18-4+10 Distribute Parentheses

-22+10 Do subtraction

-12 Do Addition

4 0

3 years ago

Read 2 more answers

Please help! Segment QR is tangent to circle P at point Q. What is the measure of angle PQR? A.) 37 degrees B.) 53 degrees C.) 9

Andrew [12]

Answer:

Correct option: C) 90 degrees

Step-by-step explanation:

When we have a tangent segment to a circle, the angle made with the radius of the circle and the tangent segment is always a right angle, that is, 90 degrees. In other words, the radius and the tangent segment are always perpendicular.

If QR is tangent to the circle P, and PQ is the radius of the circle, the segment PQ is perpendicular to the segment QR, so the angle PQR is equal 90 degrees.

Correct option: C)

6 0

3 years ago

The line with the slope of -8 passing through (-11,7)

Dahasolnce [82]

Slope intercept form y = -8x - 81
Point slope form (y - 7) = -8 (x + 11)

5 0

3 years ago