Question

HELP ME ANSWER ASAP PLEASE!

Answer 1

By the Pythagorean theorem, $IH=\sqrt{8^{2}-3^{2}}=\sqrt{55}$.

So,

$\sin J=\frac{\sqrt{55}}{8}\\\\\cos J=\frac{3}{8}\\\\\tan J=\frac{\sqrt{55}}{3}$