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-BARSIC- [3]
4 years ago
12

Anyone know the answer? THANK YOU

Mathematics
1 answer:
svetlana [45]4 years ago
7 0

Answer:

The one on the top left

Step-by-step explanation:

Slope of one third and y intercept -4

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How do I solve this
anastassius [24]
\bf \cfrac{x+2}{x^2+6x-7}    so, that function is "defined", ok, what values of "x" are not in the domain, namely, what values can "x" take on and not make the function "undefined", well,  you know, if we end up with a 0 at the denominator, like   \bf \cfrac{x+2}{0}    then, we'd have an "undefined" expression...so... any values of "x" that make the denominator 0, are not really the ones we want, and thus they'd be excluded from the domain.


so, hmm which are those? let's check, let's set the denominator to 0, and solve for "x".

\bf x^2+6x-7=0\implies (x+7)(x-1)=0\implies x=&#10;\begin{cases}&#10;-7\\&#10;1&#10;\end{cases}&#10;\\\\\\&#10;\textit{let's check, } x=-7\quad \cfrac{(-7)+2}{(-7)^2+6(-7)-7}\implies \cfrac{-5}{49-42-7}\implies \cfrac{-5}{0}&#10;\\\\\\&#10;x=1\quad \cfrac{(1)+2}{(1)^2+6(1)-7}\implies \cfrac{3}{1+6-7}\implies \cfrac{-3}{0}
7 0
4 years ago
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