You have a bag of 12 blue marbles and 12 red marbles. each are labeled 1-12. so you have 24 marbles in total (1-12 for each colo r). you draw one at random, put it back in the bag, and draw the second one.
what is the probability of the first marble being blue and the second marble being red?
2 answers:
Answer:
The probability of the first marble being blue and second being red is a 50/50 because you have 12 red and 12 blue so 50/50
Step-by-step explanation:
Answer:
the probability of you drawing a blue first then drawing a red would be a 50/50 chance with 50 leaning toward you meaning it's very high but might not happen as well
Step-by-step explanation:
You might be interested in
Take the like terms on one side: 2m=6-14 2m = 8 m= 8/2 m= 4
Answer:
0.30
Step-by-step explanation:
Each number was getting divided by 3 each time
Answer:
2^-3
Step-by-step explanation:
C=7n because 28 divided 4 is 7 7 is the proportional
31 because two more tens is equal to 20. so 20+11 is 31