When you arrange the N points in sequence around the polygon (clockwise or counterclockwise), the area is half the magnitude of the sum of the determinants of the points taken pairwise. The N determinants will also include the one involving the last point and the first one.
For example, consider the vertices of a triangle: (1,1), (2,3), (3,-1). Its area can be computed as
(1/2)*|(1*3-1*2) +(2*-1-3*3) +(3*1-(-1)*1)|
= (1/2)*|1 -11 +4| = 3
Answer:
c/d = 6
Step-by-step explanation:
Use the second equation.
c - 6d = 0
Add 6d to both sides.
c = 6d
Divide both sides by d.
c/d = 6
Answer:
Step-by-step explanation:
First, we expand the equation using the distributive rule:
Hence, 
Simplify: 
Add like terms:
Subtract 13 from both sides: 
Divide both sides by -8:
Answer:
C, D, E, F
Step-by-step explanation:
Remember y=mxb?
m is slope and b is y-intercept
so y=2/7x-9
Remember that slope is RISE/RUN so for every 2 squares that you go up, you go 7 squares to the right.
Also remember that since your graph is going thru your Cartiesian Plane in quadrent 4, your y value in your ordered pairs will most probably be a negative.
Please see the image to help you viualize this.
Congruent triangles are all the same. Given that the faces of a triangular pyramid are congruent then all its faces are the same. It is also good to note that this pyramid has 4 faces. Given that the surface area of the pyramid is 372m^2, the area of one face will be:
area=(total area)/(number of faces)
=372/4
=93 m^2
