Answer:
x^2+2x+y^2−2y−7=0
Step-by-step explanation:
The method from converting to standard to general is very simple
this equation in standard form would be
(x+1)^2+(y-1)^2=9
This is because whatever the center of the circle is, you take the negative/positive version of that number
The center is at -1, 1. So it would flip to be put into the equation as 1, -1.
9 is the radius^2.
The radius is 3.
To convert to general form you just simplify
x^2+1+2x = (x+1)^2
y^2 + 1 -2y = (y-1)^2
x^2 - 2x + y^2 - 2y + 2 = 9
get the nine on the left side
x^2 -2x +y^2 - 2y 2 - 9 = 0
x^2+2x+y^2−2y−7=0
Give brainliest, please!
Hope this helps :)
