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2 years ago

If f(x)=2 sin 3x+C, then the maximum value of f(x) is: 1)C 2) C+2 3) C+3 4) C+6

Mathematics

1 answer:

Vladimir79 [104]2 years ago

8 0

<h3>Answer: C+2</h3>

Reason:

The largest sin(x) can get is 1, and the same goes for sin(3x).

Consequently, the largest 2sin(3x) can get is 2.

You can visually verify these claims by graphing each function with a tool like Desmos. Take note of the y coordinate of the highest points. See below.

Therefore, the largest f(x) = 2sin(3x)+C can get is 2+C or C+2

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Mr. Franklin asked each of his 30 students to

denpristay [2]

Answer:

B) 14

Step-by-step explanation:

1/5 + 1/3 = x (don't worry, it's not algebra, I'm just using x as an example)

The common denominator is 15, so you multiply 5 by 3 = 15 and 1 by 3 = 3,

3/15 = 1/5

Then, multiply 3 by 5 = 15 and then 1 by 5 = 5, so it's

5/15 = 1/3

5/15 + 3/15 = 8/15 and then multiply 15 by 2 = 30 (number of students) and because you multiplied 15 by 2, you also multiply 8 by 2 = 16

So it is now 16/30, so you do 30-16 which is 14.

14 students chose Station M (doesn't sound like a good station).

Whoo! Let's go! (I'll stop being cringy now).

6 0

3 years ago

Read 2 more answers

6 out of the 60 employees at the sports shop are part-time employees. What percentage of the employees at the sports shop work p

Serhud [2]

Percentage of part time employees = (part-time employees/total employees) * 100 = (6/60) * 100 = 1/10 * 100 = 10%

6 0

3 years ago

Translate the question into a mathematical expression. The quotient of two and a number times seven

goblinko [34]

Answer:

2n * 7

Step-by-step explanation:

3 0

3 years ago

A clothing store determines that in order to sell x shirts, the price per shirt should be p(x)=100−x dollars. Getting x shirts f

vredina [299]

Answer:

x= -40

Step-by-step explanation:

Cost

C(x)=1,600+20x

P(x)=100-x

Revenue=x*p(x)

=x*(100-x)

=100x-x^2

Cost=Revenue

1600+20x=100x-x^2

1600+20x-100x+x^2=0

1600-80x+x^2=0

Solve using quadratic formula

Formula where

a = 1, b = 80, and c = 1600

x=−b±√b2−4ac/2a

x=−80±√80^2−4(1)(1600) / 2(1)

x=−80±√6400−6400 / 2

x=−80±√0 / 2

The discriminant b^2−4ac=0

so, there is one real root.

x= −80/2

x= -40

5 0

3 years ago

What is the difference? StartFraction x Over x squared minus 16 EndFraction minus StartFraction 3 Over x minus 4 EndFraction Sta

katovenus [111]

Answer:

The option "StartFraction negative 2 (x + 6) Over (x + 4) (x minus 4) EndFraction" is correct

That is $\frac{-2(x+6)}{(x+4)(x-4)}$

Therefore $\frac{x}{x^2-16}-\frac{3}{x-4}=\frac{-2(x+6)}{(x+4)(x-4)}$

Step-by-step explanation:

Given problem is StartFraction x Over x squared minus 16 EndFraction minus StartFraction 3 Over x minus 4 EndFraction

It can be written as below :

$\frac{x}{x^2-16}-\frac{3}{x-4}$

To solve the given expression

$\frac{x}{x^2-16}-\frac{3}{x-4}$

$=\frac{x}{x^2-4^2}-\frac{3}{x-4}$

$=\frac{x}{(x+4)(x-4)}-\frac{3}{x-4}$ ( using the property $a^2-b^2=(a+b)(a-b)$ )

$=\frac{x-3(x+4)}{(x+4)(x-4)}$

$=\frac{x-3x-12}{(x+4)(x-4)}$ ( by using distributive property )

$=\frac{-2x-12}{(x+4)(x-4)}$

$=\frac{-2(x+6)}{(x+4)(x-4)}$

$\frac{x}{x^2-16}-\frac{3}{x-4}=\frac{-2(x+6)}{(x+4)(x-4)}$

Therefore $\frac{x}{x^2-16}-\frac{3}{x-4}=\frac{-2(x+6)}{(x+4)(x-4)}$

Therefore the option "StartFraction negative 2 (x + 6) Over (x + 4) (x minus 4) EndFraction" is correct

That is $\frac{-2(x+6)}{(x+4)(x-4)}$

5 0

4 years ago

Read 2 more answers