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Andru [333]
3 years ago
8

Simplify and expand (1/3)to 2nd power × 18 + (1/2)to 2nd power × 4

Mathematics
1 answer:
Pepsi [2]3 years ago
6 0
Step 1. Use Division Distributive Property ( \frac{x}{y} ) ^{a} = \frac{ x^{a} }{ y^{a} }

Step 2. Simplify 3^{2} to 9

\frac{1}{9} *18+( \frac{1}{2} ) ^{2}*4 


Step 3. Use Division Distributive Property  ( \frac{x}{y} ) ^{a} = \frac{ x^{a} }{ y^{a} }

\frac{1}{9} *18+ \frac{1}{ 2^{2} } *4

Step 4. Simplify 2^{2} to 4

\frac{1}{9} *18+ \frac{1}{4} *4

Step 5. Simplify \frac{1}{9} *18 to \frac{18}{9}

\frac{18}{9} + \frac{1}{4} *4

Step 6. Simplify \frac{18}{9} to 2

2+ \frac{1}{4} *4

Step 7. Simplify \frac{1}{4} *4 to 1

2+1

Step 8. Simplify

3

Done! Your answer is 3 
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8 0
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which digit can replace the? to make this number sentence true 736,554 < 7?6,573 < 736,589 only one answer
mars1129 [50]
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8 0
3 years ago
Find the quotient for 63÷8 showing work
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5 0
3 years ago
Which option lists am expression that is not equivalent to 4^2/3
Vesnalui [34]

remember that

x^{\frac{a}{b}}=\sqrt[b]{x^a}

also x^{-a}=\frac{1}{x^a}

and (a^b)^c=a^{bc}


so

4^{\frac{2}{3}}


first one, that one is clearly not equal since 0.25≠4

2nd one, 0.25=1/4, so 0.25^{\frac{-2}{3}}=(\frac{1}{4})^{\frac{-2}{3}=  \frac{1}{(\frac{1}{4})^{\frac{2}{3}}}=4^{\frac{2}{3}}, which matches

3rd one, \sqrt[3]{16}=\sqrt[3]{4^2}=4^{\frac{3}{2}}, which matches

4th one (\sqrt[3]{4})^2=(4^{\frac{1}{3}})^2=4^{\frac{2}{3}} which matches


answer is 0.25^{\frac{2}{3}}

4 0
3 years ago
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