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Andru [333]
3 years ago
8

Simplify and expand (1/3)to 2nd power × 18 + (1/2)to 2nd power × 4

Mathematics
1 answer:
Pepsi [2]3 years ago
6 0
Step 1. Use Division Distributive Property ( \frac{x}{y} ) ^{a} = \frac{ x^{a} }{ y^{a} }

Step 2. Simplify 3^{2} to 9

\frac{1}{9} *18+( \frac{1}{2} ) ^{2}*4 


Step 3. Use Division Distributive Property  ( \frac{x}{y} ) ^{a} = \frac{ x^{a} }{ y^{a} }

\frac{1}{9} *18+ \frac{1}{ 2^{2} } *4

Step 4. Simplify 2^{2} to 4

\frac{1}{9} *18+ \frac{1}{4} *4

Step 5. Simplify \frac{1}{9} *18 to \frac{18}{9}

\frac{18}{9} + \frac{1}{4} *4

Step 6. Simplify \frac{18}{9} to 2

2+ \frac{1}{4} *4

Step 7. Simplify \frac{1}{4} *4 to 1

2+1

Step 8. Simplify

3

Done! Your answer is 3 
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X < -40.5

To find this, here are the steps:

Combine like terms like so:

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-4x > 162

Then divide by negative four. Don’t forget, dividing by negatives switches the way the sign points so your final product will be:

x < -40.5

Hope this helps!
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What is the equation of this line in standard form?
horsena [70]

Option B 6x-7y = -11 is correct

Step-by-step explanation:

We need to write the equation of the given line in standard form.

The points are (1/2,2) and (3,1)

The equation used is:

y-y_{1}=m(x-x_{1})

where m is the slope.

Finding slope :

m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

x₁= 1/2, y₁=2, x₂=-3, y₂=-1

Putting values:

m=\frac{-1-2}{-3-1/2} \\m=\frac{6}{7}

Now taking point (1/2,2) and s;ope m = 6/7 finding equation:

y-y_{1}=m(x-x_{1})

y-2=\frac{6}{7}(x-\frac{1}{2})\\  7(y-2)=6(x-\frac{1}{2})\\7y-14=6x-3\\7y-6x=-3+14\\7y-6x= 11\\Multiply \,\,with\,\, -1\\-7y+6x=-11\\6x-7y=-11

So, Option B 6x-7y=-11 is correct

Keywords: Standard form of equation

Learn more about Standard form of equation at:

  • brainly.com/question/4097107
  • brainly.com/question/12954015
  • brainly.com/question/1979240

#learnwithBrainly

5 0
3 years ago
Find the equation of the line that
Aleonysh [2.5K]

Answer:

y = 3x/2-14

Step-by-step explanation:

We are given that the line is perpendicular to y = -2/3 and contains (4,-8).

<u>P</u><u>e</u><u>r</u><u>p</u><u>e</u><u>n</u><u>d</u><u>i</u><u>c</u><u>u</u><u>l</u><u>a</u><u>r</u><u> </u><u>D</u><u>e</u><u>f</u><u>.</u>

\displaystyle \large{m_1m_2 =  - 1}

Both slopes multiply each others equal to -1.

Finding another slope that is perpendicular to -2/3, substitite m1 = -2/3 in.

\displaystyle \large{ -  \frac{2}{3} m_2 =  - 1}

Multiply both sides by 3.

\displaystyle \large{ -  \frac{2}{3} m_2( 3) =  - 1(3)} \\  \displaystyle \large{ -  2 m_2=  - 3} \\  \displaystyle \large{  m_2=  \frac{3}{2} }

Therefore, another slope that is perpendicular to -2/3 is 3/2.

Then rewrite in slope-intercept form.

<u>S</u><u>l</u><u>o</u><u>p</u><u>e</u><u>-</u><u>I</u><u>n</u><u>t</u><u>e</u><u>r</u><u>c</u><u>e</u><u>p</u><u>t</u>

\displaystyle \large{y  = mx + b}

where m = slope and b = y-intercept; substitute m = 3/2 in.

\displaystyle \large{y  =  \frac{3}{2} x + b}

Since the line contains (4,-8), substitute x = 4 and y = -8 in and solve for b.

\displaystyle \large{ - 8 =  \frac{3}{2} (4) + b} \\  \displaystyle \large{ - 8 =  3(2)+ b} \\  \displaystyle \large{ - 8 =  6 +  b} \\  \displaystyle \large{ - 8 - 6 =  b} \\  \displaystyle \large{ - 14 =  b}

Therefore, b is -14; rewrite again in slope-intercept form.

Thus:-

\displaystyle \large{y  =  \frac{3}{2} x + b} \\  \displaystyle \large{y  =  \frac{3}{2} x  - 14}

4 0
2 years ago
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