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Andru [333]
3 years ago
8

Simplify and expand (1/3)to 2nd power × 18 + (1/2)to 2nd power × 4

Mathematics
1 answer:
Pepsi [2]3 years ago
6 0
Step 1. Use Division Distributive Property ( \frac{x}{y} ) ^{a} = \frac{ x^{a} }{ y^{a} }

Step 2. Simplify 3^{2} to 9

\frac{1}{9} *18+( \frac{1}{2} ) ^{2}*4 


Step 3. Use Division Distributive Property  ( \frac{x}{y} ) ^{a} = \frac{ x^{a} }{ y^{a} }

\frac{1}{9} *18+ \frac{1}{ 2^{2} } *4

Step 4. Simplify 2^{2} to 4

\frac{1}{9} *18+ \frac{1}{4} *4

Step 5. Simplify \frac{1}{9} *18 to \frac{18}{9}

\frac{18}{9} + \frac{1}{4} *4

Step 6. Simplify \frac{18}{9} to 2

2+ \frac{1}{4} *4

Step 7. Simplify \frac{1}{4} *4 to 1

2+1

Step 8. Simplify

3

Done! Your answer is 3 
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3 years ago
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dusya [7]

Answer:

\large\boxed{\dfrac{41p}{70q^4(r-9)^2}}

Step-by-step explanation:

\dfrac{2p^4}{5q^5(r-9)^3}\cdot\dfrac{41q(r-9)}{28p^3}\\\\=\dfrac{2\!\!\!\!\diagup^1\cdot41}{5\cdot28\!\!\!\!\!\diagup_{14}}\cdot\dfrac{q\!\!\!\!\diagup}{q^{5\!\!\!\!\diagup^4}}\cdot\dfrac{(r\!\!\!\!\!\!{--}-9)\!\!\!\!\!\!{--}}{(r-9)^{3\!\!\!\!\diagup^2}}\cdot\dfrac{p^{4\!\!\!\!\diagup}}{p^3\!\!\!\!\!\!\diagup}\\\\=\dfrac{41}{70}\cdot\dfrac{1}{q^4}\cdot\dfrac{1}{(r-9)^2}\cdot\dfrac{p}{1}\\\\=\dfrac{41p}{70q^4(r-9)^2}

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