The answer for the first question is a. In this problem, we are trying to figure out any numbers that belong to both set X and Y. Set X, has numbers that are less than 10. {etc... -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9} This can go on forever, because there is no specified limitation, besides the numbers having to be lower than 10. Set Y, has numbers that are even. {etc... -4, -2, 0, 2, 4, 6, 8, 10, 12, etc...} This also can go on forever, because there is no specified limitation, besides the numbers having to be even. The only numbers that belong in both set X and Y are {0, 2, 4, 6, 8}. Therefore, answer to the problem is a: {0, 2, 4, 6, 8}.
The answer for the second question is a. You need to replace z with 0, 1, 2, or 3 and solve the equation on the right side of the inequality sign. The answer to the equation must be less than 6. If you replace z with 0: 0 (10-0) = 0. 0 is less than 6. If you replace z with 1: 1 (10-1) = 9. 9 is greater than 6. If you replace z with 2: 2 (10-2) = 16. 16 is greater than 6. If you replace z with 3: 3 (10-3) = 21. 21 is greater than 6. Therefore, 0 is the answer.
There are 5 x 10^6 blood cells in a ml, and 473 ml in a pint. simply multiply both numbers together and put the answer in scientific notation (one digit before the decimal)
Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10. A triangle MPN is right and <span>isosceles, because </span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10. The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units. Area of KLMN is egual to sq. units.
First, we can plot these points on a graph. Then, we’ll use the Distance Formula to calculate the distance between the two points, which is sqrt(181).
Since the problem tells us that one of our coordinates is the midpoint of K, we know that the length of the segment we just calculated is 1/2 of K. We can multiply our answer to get that K is 2 times sqrt(181).