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Goshia [24]
3 years ago
6

Please Help!!! I'll make you Brainliest!!! Thanks :)

Mathematics
2 answers:
Romashka-Z-Leto [24]3 years ago
8 0
The answer for the second one is 0.
anygoal [31]3 years ago
8 0
The answer for the first question is a.
In this problem, we are trying to figure out any numbers that belong to both set X and Y.
Set X, has numbers that are less than 10. {etc... -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9} This can go on forever, because there is no specified limitation, besides the numbers having to be lower than 10.
Set Y, has numbers that are even. {etc... -4, -2, 0, 2, 4, 6, 8, 10, 12, etc...} This also can go on forever, because there is no specified limitation, besides the numbers having to be even.
The only numbers that belong in both set X and Y are {0, 2, 4, 6, 8}.
Therefore, answer to the problem is a: {0, 2, 4, 6, 8}.

The answer for the second question is a.
You need to replace z with 0, 1, 2, or 3 and solve the equation on the right side of the inequality sign. The answer to the equation must be less than 6.
If you replace z with 0: 0 (10-0) = 0. 0 is less than 6.
If you replace z with 1: 1 (10-1) = 9. 9 is greater than 6.
If you replace z with 2: 2 (10-2) = 16. 16 is greater than 6.
If you replace z with 3: 3 (10-3) = 21. 21 is greater than 6.
Therefore, 0 is the answer.
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Step-by-step explanation:

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<h2>MARK ME AS BRAINLIST</h2><h3>PLZ FOLLOW ME</h3>
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3 years ago
Evaluate the expression
Lilit [14]

Answer:

<h2>2^7</h2>

Multiply

2^3 by 2^4 by adding the exponents.

Use the power rule

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2^3+4

Add 3 and 4.

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Raise 2 to the power of 7.

128

Step-by-step explanation:

Hope it is helpful....

7 0
3 years ago
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