What is the answer for this math question
2 answers:
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Answer:
The car travels 40 miles while the plane travels 600 miles.
Step-by-step explanation:
This problem can be solved by rules of three.
In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.
When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too.
When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease.
In this problem, all the measures have direct relationship.
The first step is knowing how much the plane travels in a hour.
The problem states that in a minute, the plane travels 15 miles. How much does it travel in 60 minutes.
1 minute - 15 miles
60 minutes - x miles
x = 60*15
x = 900 miles
In a hour, the plane travels 900 miles.
Then we need to know how long it takes for the plane to travel 600 miles.
1 hour - 900 miles
x hours - 600 miles
900x = 600
x = 0.667 hours = 40 minutes.
Finally, we discover how much the car travels in 40 minutes.
The problem states that in a hour(60 minutes), the car travels 60 miles, so:
60 miles - 60 minutes
x miles - 40 minutes
60x = 2400
x = 40 miles.
The car travels 40 miles while the plane travels 600 miles.
Hello,
We know that if we make the same operation on both sides, we don't affect the equation:
For example:
Do you see? we add 2 on both sides and we don't affect the equality
We can do the same with the multiplication, for example
4=4 (i'll multiply both sides by 1/2)
Now, we do exactly the same in your excercise:
![P=2(L+W) \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,[multiply\,\,by\,\,1/2] \\ \\ P*\bold{ \frac{1}{2}}=2(L+W)*\bold{ \frac{1}{2}} \\ \\ \frac{P}{2}=L+W\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,[Subtract\,\,L]\\ \\ \frac{P}{2}-\bold{L}=L+W-\bold{L}\\ \\ \frac{P}{2}-\bold{L}=L-\bold{L}+W \\ \\ \frac{P}{2}-L=W\\ \\ \boxed{ W= \frac{P}{2}-L }](https://tex.z-dn.net/?f=P%3D2%28L%2BW%29%20%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5Bmultiply%5C%2C%5C%2Cby%5C%2C%5C%2C1%2F2%5D%20%5C%5C%20%5C%5C%20P%2A%5Cbold%7B%20%5Cfrac%7B1%7D%7B2%7D%7D%3D2%28L%2BW%29%2A%5Cbold%7B%20%5Cfrac%7B1%7D%7B2%7D%7D%20%5C%5C%20%20%5C%5C%20%5Cfrac%7BP%7D%7B2%7D%3DL%2BW%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5BSubtract%5C%2C%5C%2CL%5D%5C%5C%20%20%5C%5C%20%5Cfrac%7BP%7D%7B2%7D-%5Cbold%7BL%7D%3DL%2BW-%5Cbold%7BL%7D%5C%5C%20%20%5C%5C%20%5Cfrac%7BP%7D%7B2%7D-%5Cbold%7BL%7D%3DL-%5Cbold%7BL%7D%2BW%20%5C%5C%20%20%5C%5C%20%5Cfrac%7BP%7D%7B2%7D-L%3DW%5C%5C%20%5C%5C%20%5Cboxed%7B%20W%3D%20%5Cfrac%7BP%7D%7B2%7D-L%20%7D)
We know that if we make the same operation on both sides, we don't affect the equation:
For example:
Do you see? we add 2 on both sides and we don't affect the equality
We can do the same with the multiplication, for example
4=4 (i'll multiply both sides by 1/2)
Now, we do exactly the same in your excercise:
Answer:
Step-by-step explanation:
From the question we are told that:
Mean
Standard deviation
Significance level
Therefore
Confidence level
From table
Generally the equation for Z-score is mathematically given by