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Bezzdna [24]
3 years ago
15

What is the answer for this math question

Mathematics
2 answers:
pav-90 [236]3 years ago
7 0
1/10÷2/3=KCF (keep,change,flip)
1/10×3/2=3/20 cups
0.15=15%=3/20 as decimal*percent
Leviafan [203]3 years ago
6 0

0.15 Is this the answer you were looking for?

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I need some help plz
scZoUnD [109]

Answer:

  one solution is (0, -2)

Step-by-step explanation:

The line y = -x is the boundary of the solution space of the first inequality. The less-than symbol (<) tells you that the line will be dashed and the shading will be below it. The line has a slope of -1 and goes through the y-intercept point (0, 0).

The line y = x - 2 is the boundary of the solution space for the second inequality. The less-than-or-equal-to symbol (≤) tells you the line will be solid (or equal to) and the shading will be below it (less than). The line has a slope of +1 and goes through the y-intercept point (0, -2).

The area of the graph where the shadings overlap is the solution space for the system of inequalities. Any point in that area will do, including points on the solid line where y < -x. (0, -2) is one such point.

3 0
3 years ago
What is the solution to 3|x + 3| = 12?
Neporo4naja [7]

Step-by-step explanation:

3(x+3)=12

3x+9=12

3x=12-9

3x=3

x=1

7 0
3 years ago
Ivan used coordinate geometry to prove that quadrilateral EFGH is a square.
Gelneren [198K]

Answer:

(A)Segment EF, segment FG, segment GH, and segment EH are congruent

Step-by-step explanation:

<u>Step 1</u>

Quadrilateral EFGH with points E(-2,3), F(1,6), G(4,3), H(1,0)

<u>Step 2</u>

Using the distance formula

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Given E(-2,3), F(1,6)

|EF|=\sqrt{(6-3)^2+(1-(-2))^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}

Given F(1,6), G(4,3)

|FG|=\sqrt{(3-6)^2+(4-1)^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}

Given G(4,3), H(1,0)

|GH|=\sqrt{(0-3)^2+(1-4)^2}=\sqrt{(-3)^2+(-3)^2}=\sqrt{18}=3\sqrt{2}

Given E (−2, 3), H (1, 0)

|EH|=\sqrt{(0-3)^2+(1-(-2))^2}=\sqrt{(-3)^2+(3)^2}=\sqrt{18}=3\sqrt{2}

<u>Step 3</u>

Segment EF ,E (−2, 3), F (1, 6)

Slope of |EF|=\frac{6-3}{1+2} =\frac{3}{3}=1

Segment GH, G (4, 3), H (1, 0)

Slope of |GH|= \frac{0-3}{1-4} =\frac{-3}{-3}=1

<u>Step 4</u>

Segment EH, E(−2, 3), H (1, 0)

Slope of |EH|= \frac{0-3}{1+2} =\frac{-3}{3}=-1

Segment FG, F (1, 6,) G (4, 3)

Slope of |EH| =\frac{3-6}{4-1} =\frac{-3}{3}=-1

<u>Step 5</u>

Segment EF and segment GH are perpendicular to segment FG.

The slope of segment EF and segment GH is 1. The slope of segment FG is −1.

<u>Step 6</u>

<u>Segment EF, segment FG, segment GH, and segment EH are congruent. </u>

The slope of segment FG and segment EH is −1. The slope of segment GH is 1.

<u>Step 7</u>

All sides are congruent, opposite sides are parallel, and adjacent sides are perpendicular. Quadrilateral EFGH is a square

4 0
3 years ago
Read 2 more answers
I NEED ASAP DUE IN 20 MINS
11111nata11111 [884]

Answer:

y = 45 / 2x + 50

Step-by-step explanation:

The best equation for the line of the best fit would be y = 45 / 2x + 50.

The slope would be 45 / 2 and the y-intercept would be ( 0 , 50 ).

I used the points, ( 0 , 50 ) and ( 4 , 140 ) to get the equation, slope, and the y-intercept.

I used those points because they were the most accurate ones that I know for now.

Also, remember the formula is, "y = mx + b."

4 0
3 years ago
Help please! I need the answers for the two fill-in-the-blanks.
ryzh [129]

Answer:

The first column is transformation

The second one I have forgotten

Need other help

3 0
4 years ago
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