Prolly not the best person to answer this question lol
Answer:
y= 14
Step-by-step explanation:
Given that AC= BC, △ABC is an isosceles triangle.
∠CBA= ∠CAB (base ∠s of isos. △)
∠CBA= 50°
∠ACB +50° +50°= 180° (∠ sum of △ABC)
∠ACB +100°= 180°
∠ACB= 180° -100°
∠ACB= 80°
Given that ∠ACB= (5y +10)°,
(5y +10)°= 80°
5y +10= 80
5y= 80 -10 <em>(</em><em>-10</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>
5y= 70 <em>(</em><em>simplify</em><em>)</em>
y= 70 ÷5 <em>(</em><em>÷</em><em>5</em><em> </em><em>throughout</em><em>)</em>
y= 14
Answer:
0.11871069182
Step-by-step explanation:
((10/12) - (3/(8 10/12))) - (3/8) = 0.11871069182
270 degrees because a whole circle is 360 degrees so 360×3/4=270
A (-4,5)
B (-3,1)
C (-5,2)
A'(3,1)
B'(2,5)
C'(4,4)