Question

Find the area of the quadrilateral QRST by using the formula for the area of a kite. HELP PLEASE!!!!

Answer 1

ANSWER

A. 15 units^2

EXPLANATION

The area of kite is half the product of the diagonals.

The first diagonal has vertices at,

T(0,0) and R(5,5).

The length of this diagonal is

$TR = \sqrt{ {5}^{2} + {5}^{2} }$

$TR = \sqrt{25 + 25}$

$TR = \sqrt{50} =5 \sqrt{2}$

The other diagonal has vertices at;

Q(0,3) and S(3,0).

The length of this diagonal is

$QS = \sqrt{ {3}^{2} + {3}^{2} }$

$QS = \sqrt{ 9+ 9 }$

$QS = \sqrt{18} = 3 \sqrt{2}$

The area of the kite is

$= \frac{1}{2} \times 3 \sqrt{2} \times 5 \sqrt{2}$

$= 15 \: {units}^{2}$