7x^2+3y^2+12x+2y-6=0 Help me find the value of a,b,c and the discriminant number

Mathematics

1 answer:

Mrac [35]1 year ago

7 0

Answer:

b o a h d

Step-by-step explanation:

1*5 3%9 46% &45 that is the answer

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The average amount of a beverage in randomly selected 16-ounce beverage can is 16.18 ounces with a standard deviation of 0.4 oun

Artist 52 [7]

Answer:

The probability that the mean of this sample is less than 16.1 ounces of beverage is 0.0537.

Step-by-step explanation:

We are given that the average amount of a beverage in randomly selected 16-ounce beverage can is 16.18 ounces with a standard deviation of 0.4 ounces.

A random sample of sixty-five 16-ounce beverage cans are selected

Let $\bar X$ = sample mean amount of a beverage

The z-score probability distribution for the sample mean is given by;

Z = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean amount of a beverage = 16.18 ounces

$\sigma$ = standard deviation = 0.4 ounces

n = sample of 16-ounce beverage cans = 65

Now, the probability that the mean of this sample is less than 16.1 ounces of beverage is given by = P( $\bar X$ < 16.1 ounces)

P( $\bar X$ < 16.1 ounces) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{16.1-16.18}{\frac{0.4}{\sqrt{65} } }$ ) = P(Z < -1.61) = 1 - P(Z $\leq$ 1.61)