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monitta
4 years ago
14

Which even definition corresponds to exactly one outcome of the experiment?

Mathematics
1 answer:
s2008m [1.1K]4 years ago
7 0
Jsjdjdjndndnsjshshsgsgsgdhdhdhdjdjndnfnf
You might be interested in
Can an expert help with this
SVEN [57.7K]

The formula of an area of a circle:

A_O=\pi r^2

We have

r = 1.8 m

π ≈ 3.14

Substitute:

A_O=\pi\cdot1.8^2=3.24\pi\ m^2\approx3.24\cdot3.14=10.1736\ m^2\approx10.17\ m^2

7 0
3 years ago
Three times the difference of four times a number n and seven is no more than one
Sindrei [870]

Answer:

3x-4x7

Step-by-step explanation:

8 0
3 years ago
A fraction becomes 4÷5 if 1 is added to both numerator and denominator. If, however, 5 is subtracted from both numerator and den
tia_tia [17]

Answer:

\dfrac{7}{9}

Step-by-step explanation:

\dfrac{x+1}{y+1}=\dfrac{4}{5}\\\Rightarrow 5x-4y=-1

\dfrac{x-5}{y-5}=\dfrac{1}{2}\\\Rightarrow 2x-y=5

Putting it in matrix form

\begin{bmatrix}a_{1}&b_{1}\\a_{2}&b_{2}\end{bmatrix}{\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}{c_{1}}\\{c_{2}}\end{bmatrix}\\\Rightarrow\begin{bmatrix}5 & -4\\2 & -1\end{bmatrix}\begin{bmatrix}x\\ y\end{bmatrix}=\begin{bmatrix}-1\\ 5\end{bmatrix}

From Cramer's rule we have

x=\dfrac{\begin{vmatrix}c_1 &b_1 \\ c_2 & b_2\end{vmatrix}}{\begin{vmatrix}a_1 &b_1 \\ a_2& b_2\end{vmatrix}}\\\Rightarrow x=\dfrac{\begin{vmatrix}-1 &-4 \\ 5 & -1\end{vmatrix}}{\begin{vmatrix}5 &-4 \\ 2& -1\end{vmatrix}}\\\Rightarrow x=\dfrac{1+20}{-5+8}\\\Rightarrow x=7

y=\dfrac{\begin{vmatrix}a_1 &c_1 \\ a_2 & c_1\end{vmatrix}}{\begin{vmatrix}a_1 &b_1 \\ a_2& b_2\end{vmatrix}}\\\Rightarrow y=\dfrac{\begin{vmatrix}5 &-1 \\ 2 & 5\end{vmatrix}}{\begin{vmatrix}5 &-4 \\ 2& -1 \end{vmatrix}}\\\Rightarrow y=\dfrac{25+2}{-5+8}\\\Rightarrow y=9

Verifying the results

\dfrac{7+1}{9+1}=\dfrac{8}{10}=\dfrac{4}{5}

\dfrac{7-5}{9-5}=\dfrac{2}{4}=\dfrac{1}{2}

Hence, the fraction is \dfrac{7}{9}.

6 0
3 years ago
They were skew
EleoNora [17]
I can’t see the picture
6 0
3 years ago
Simplify by factoring. Assume that all expressions under radicals represent nonnegative numbers.
Nimfa-mama [501]
<h2>Answer:</h2>

<u>x>0 and working with real numbers</u>

10x^2\sqrt{2}

OR

<u>x<0 and working with imaginary/complex numbers</u>

10\sqrt{2}\sqrt{x^4}

OR

<u>Leave it like the following for both systems(Real/Complex) numbers</u>

10\sqrt{2}\sqrt{x^4}

<h2>Step-by-step explanation:</h2>

\sqrt{200x^4}

<u>First simplify</u> \sqrt{200}

\sqrt{200}

<u>Find a perfect square and a non perfect square, which when you multiply the two squares it gives you</u> \sqrt{200}

\sqrt{100} * \sqrt{2} = \sqrt{200}

\sqrt{100} \ \sqrt{2}}

10 \sqrt{2}

<u>Now get the square root of</u> \sqrt{x^4} <u>if we are working with real numbers and  x > 0</u>

\sqrt{x^4} = x^2

<u>If x not > 0 then just leave as</u> \sqrt{x^4}

<u>Now combine it all</u>

10x^2\sqrt{2}

OR

10\sqrt{2}\sqrt{x^4}

5 0
3 years ago
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