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1 year ago

Please help!

Mathematics

2 answers:

SSSSS [86.1K]1 year ago

5 0

A the correct answer pa brainless po

Morgarella [4.7K]1 year ago

4 0

Answer:

substitution

Step-by-step explanation:

Vertical angles are applicable for parallel lines.

Here the scenario is triangles share a side means they have one common side.

So we can substitute that sides triangle ratios to another triangle

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Please my brother needs help fast for his work

Anastasy [175]

Answer:

Here is what I found:

Step-by-step explanation:

Please mark brainliest :) I hope it helps him!

4 0

3 years ago

A source of laser light sends rays AB and AC toward two opposite walls of a hall. The light rays strike the walls at points B an

Nataly [62]

Answer:

The distance between the walls is 70 m.

Step-by-step explanation:

Given: A source of laser light is at point A on the ground between two parallel walls BE and CD . The walls are perpendicular to the ground that is

BE ⊥ ED and CD ⊥ ED

AB is a ray of light which strikes the wall on the left at point B which is 30 meters above the ground. that is BE = 30 m

AC is a ray of light which strikes the wall on the right at point C. The length of AC = 80 meters.

The ray AB makes an angle of 45 degrees with the ground that is m∠BAE = 45°

The ray AC makes an angle of 60 degrees with the ground that is m∠CAD = 60°

As shown is figure attached below.

WE have to find the distance between the walls that is Length of ED

Length of ED = EA + AD

Consider the Δ AEB,

Using trigonometric ratio,

$\tan\theta=\frac{perpendicular}{base}$

Here $\theta=45^{\circ}$ , perpendicular = 30 m and base we can find.

thus,

$\tan 45^{\circ}=\frac{30}{EA}$

We know $\tan 45^{\circ}=1$

thus, EA = 30 m

Consider the Δ AEB,

Using trigonometric ratio,

$\cos\theta=\frac{base}{hypotenuse}$

Here $\theta=60^{\circ}$ , hypotenuse = 80 m and base we can find.

thus, $\cos 60^{\circ}=\frac{base}{80}$

We know, $\cos 60^{\circ}=\frac{1}{2}$

thus, Base = 40 m

AD = 40 m

Thus, the distance between the walls that is the length of ED = 30 + 40 = 70 m

4 0

2 years ago

In which number is the digit 5 one hundred times larger than it is in the number 253?

Paraphin [41]

The answer is B.
I timesed 50 by 100 and 1,000. So 5 would be in the thousands place.

7 0

2 years ago

Read 2 more answers

Use an equation to solve. What would it be ABCD? And the sum?

Zepler [3.9K]

Answer:

D. 35 + 145 = x

The sum of the angles = 180 degree

Step-by-step explanation:

$35\degree + 145\degree = x\\x=180\degree$

6 0

2 years ago

How do you do this problem?

aev [14]

f(x) = (x - 4)^2 - 1

g(x) = -(1/4) ( x - 4)^2 + 4

both the x and y values have to be the same. Start with the y values

f(x) = g(x)

(x - 4)^2 - 1 = -(1/4) (x - 4)^2 + 4 Add 1 to both sides.

(x - 4)^2 = -(1/4) (x - 4)^2 + 5 Add 1/4(x - 4)^2 to both sides.

(5/4) (x - 4)^2 = 5 Divide by 5/4 on both sides.

(x - 4)^2 = 5//(5/4)

(x - 4)^2 = (5/1)//5/4 Invert the second fraction and multiply

(x - 4)^2 = 5/1 * 4/5

(x - 4)^2 = 4 The 5s cancel

(x - 4)^2 = 4 Take the square root of both sides.

(x - 4) = +/- 2 Add 4 to each answer. Start with +2 on the right.

x - 4 + 4 = 2 + 4

x = 4 + 2 = 6

The x value that makes f(x)- g(x) = 0 is x = 6 The point is (6,3) answer.

Answer C.

================================================

You do not need this next part. It is just for completeness.

x - 4 = - 2

x = 4 -2

x = 2

What are the y values for these 2 x values?

y = (x - 4)^2 - 1

y = (6 - 4)^2 - 1

y = 4 - 1

y = 3

The point where f(x) - g(x) = 0 is (6,3) <<<<<< Answer 1

The second point is

y = (x - 4)^2 - 1

y = (2 - 4)^2 - 1

y = (-2)^2 - 1

y = 4 - 1

y = 3

The second point is (2,3). Answer 2

Note the y values are the same. You might expect that.

3 0

3 years ago

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