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3 years ago

Solve this equation 3x-√6y=3

Mathematics

1 answer:

Hunter-Best [27]3 years ago

3 0

Answer:

Step-by-step explanation:

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Rewrite in slope-intercept form.

Tap for more steps...

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Using the slope-intercept form, the y-intercept is

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Tap for more steps...

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Using the slope-intercept form, the slope is

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.In the Star Wars franchise, Yoda stands at only 66 centimeters tall. Suppose you want to see whether or not hobbits from the Lo

r-ruslan [8.4K]

Answer:

We conclude that the average height of hobbit is taller than Yoda.

Step-by-step explanation:

We are given that in the Star Wars franchise, Yoda stands at only 66 centimetres tall.

From a sample of 7 hobbits, you ﬁnd their mean height $\bar X$ = 80 cm with standard deviation s = 10.8 cm.

Let $\mu$ = average height of hobbit.

So, Null Hypothesis, $H_0$ : $\mu$ $\leq$ 66 cm {means that the average height of hobbit is shorter than or equal to Yoda}

Alternate Hypothesis, $H_A$ : $\mu$ > 66 cm {means that the average height of hobbit is taller than Yoda}

The test statistics that would be used here One-sample t test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n}}}$ ~ $t_n_-_1$

where, $\bar X$ = sample mean height = 80 cm

s = sample standard deviation = 10.8 cm

n = sample of hobbits = 7

So, test statistics = $\frac{80-66}{\frac{10.8}{\sqrt{7}}}$ ~ $t_6$

= 3.429

The value of t test statistics is 3.429.

Now, at 0.01 significance level the t table gives critical value of 3.143 for right-tailed test. Since our test statistics is more than the critical value of t as 3.429 > 3.143, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the average height of hobbit is taller than Yoda.

3 0

4 years ago

PLEASE HELP THESE ARE MULTI STEP EQUATIONS!!!!!!!!!

dusya [7]

Answer:

1.-3

2.4

3.3

4. -4

5. -4

6.3

7. -19/9

8. -3

9.0

10. -2

Step-by-step explanation:

7 0

3 years ago

Sheila bought several bags of balloons and boxes of candles. The candles cost $15 per bix, and the balloons cowt $8 per bag. She

snow_tiger [21]

Answer:

balloons= 9

candles= 8

Step-by-step explanation:

let the number of balloons be x

and candles be y

15x+8y=192----------1

x+y=17--------------2

from 2, x= 17-y

put x= 17-y in 1

15( 17-y)+8y=192

255-15y+8y=192

solve for y

-7y=192-255

-7y=-63

x=63/7

x=9

put x= 9 in 1

9+y=17

y= 17-9

y=8.

7 0

3 years ago

Please help radical expression dividing

77julia77 [94]

$\bf \cfrac{\sqrt[4]{63}}{4\sqrt[4]{6}}\qquad 
\begin{cases}
63=3\cdot 3\cdot 7\\
6=2\cdot 3
\end{cases}\implies \cfrac{\sqrt[4]{3\cdot 3\cdot 7}}{4\sqrt[4]{2\cdot 3}}\implies \cfrac{\underline{\sqrt[4]{3}}\cdot \sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}\cdot \underline{\sqrt[4]{3}}}
\\\\\\
\cfrac{\sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{3\cdot 7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}$

$\bf \textit{now, rationalizing the denominator}\\\\
\cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}\cdot \cfrac{\sqrt[4]{2^3}}{\sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21}\cdot \sqrt[4]{8}}{4\sqrt[4]{2}\cdot \sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21\cdot 8}}{4\sqrt[4]{2\cdot 2^3}}\implies \cfrac{\sqrt[4]{168}}{4\sqrt[4]{2^4}}
\\\\\\
\cfrac{\sqrt[4]{168}}{4\cdot 2}\implies \cfrac{\sqrt[4]{168}}{8}$

and is all you can simplify from it.

so... all we did, was rationaliize it, namely, "getting rid of the pesky radical at the bottom", we do so by simply multiplying it by something that will raise the radicand, to the same degree as the root, thus the radicand comes out.

6 0

3 years ago

Which situation can be represented by this equation? 2,500 + 40x = 7,300-60x

koban [17]

Answer:

x= 48

Step-by-step explanation:

$2500+40x+60x=7300\\40x+60x=7300-2500\\100x=7300+2500\\100x=4800\\x=4800/100\\x=48$

4 0

3 years ago

Solve this equation 3x-√6y=3​

Solve this equation 3x-√6y=3