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2 years ago

To the left of z = -0.95?

1 answer:

5 0

I suspect you want the area under the standard normal curve to the left of z = -0.95.

On my calculator I typed in normal cdf(-100, -0.95) and got the result 0.171.

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Two numbers are in the ratio of 2 to 3. If the smaller number is 18, the larger number is___.

Tamiku [17]

Answer:

Step-by-step explanation:

2:3

18:?

2 x 9 = 18

3 x 9 = 27

4 0

3 years ago

Read 2 more answers

Reagan used 1,297 sq ft of wrapping paper to wrap gifts for everyone in her class. If each gift used the same amount of wrapping

seraphim [82]

She used 54.04 sq ft of wrapping paper

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2 years ago

10 times as many as _ hundreds is 60 hundreds or _ thousands

Lady_Fox [76]

60 hundreds means 6000 = 6 thousands;

So, 10 · x = 6000;

x = 600;

600 means 6 hundreds;

Finally, 10 times as many as 6 hundreds is 60 hundreds or 6 thousands.

6 0

3 years ago

What's a pair of equal ratios

Kruka [31]

Y= 2x + 2 and y= 2x - 1

8 0

3 years ago

Due to a manufacturing error, two cans of regular soda were accidentally filled with diet soda and placed into a 18-pack. Suppos

crimeas [40]

Answer:

a) There is a 1.21% probability that both contain diet soda.

b) There is a 79.21% probability that both contain diet soda.

c) $P(X = 2)$ is unusual, $P(X = 0)$ is not unusual

d) There is a 19.58% probability that exactly one is diet and exactly one is regular.

Step-by-step explanation:

There are only two possible outcomes. Either the can has diet soda, or it hasn't. So we use the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

A number of sucesses $x$ is considered unusually low if $P(X \leq x) \leq 0.05$ and unusually high if $P(X \geq x) \geq 0.05$

In this problem, we have that:

Two cans are randomly chosen, so $n = 2$

Two out of 18 cans are filled with diet coke, so $\pi = \frac{2}{18} = 0.11$

a) Determine the probability that both contain diet soda. P(both diet soda)

That is P(X = 2).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 2) = C_{2,2}(0.11)^{2}(0.89)^{0} = 0.0121$

There is a 1.21% probability that both contain diet soda.

b)Determine the probability that both contain regular soda. P(both regular)

That is P(X = 0).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 0) = C_{2,0}(0.11)^{0}(0.89)^{2} = 0.7921$

There is a 79.21% probability that both contain diet soda.

c) Would this be unusual?

We have that $P(X = 2)$ is unusual, since $P(X \geq 2) = P(X = 2) = 0.0121 \leq 0.05$

For P(X = 0), it is not unusually high nor unusually low.

d) Determine the probability that exactly one is diet and exactly one is regular. P(one diet and one regular)

That is P(X = 1).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 1) = C_{2,1}(0.11)^{1}(0.89)^{1} = 0.1958$

There is a 19.58% probability that exactly one is diet and exactly one is regular.

8 0

3 years ago