The height of the kite above the ground is 58.68 ft
Let x be the height of the kite above Chee's hand.
The height of the kite above Chee's hand, the string and the horizontal distance between Chee and the kite form a right angled triangle with hypotenuse side, the length of the string and opposite side the height of the kite above Chee's hand.
Since we have the angle of elevation from her hand to the kite is 29°, and the length of the string is 100 ft.
From trigonometric ratios, we have
tan29° = x/100
So, x = 100tan29°
x = 100 × 0.5543
x = 55.43 ft.
Since Chee's hand is y = 3.25 ft above the ground, the height of the kite above the ground, L = x + y
= 55.43 ft + 3.25 ft
= 58.68 ft to the nearest hundredth of a foot
So, the height of the kite above the ground is 58.68 ft
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Answer:
A) 
B) T = -5 °C
Step-by-step explanation:
A) Let T be the change in temperature of the week. T is determined as the total temperature change (-20°C) divided by the number of weeks that have passed (4 weeks). The expression is:
B) In order to simplify the expression, simply perform the division.
This means that the temperature has dropped by 5 degrees each week.
The correct answer is C. t= 8ln(100)
Hope this helped! :)
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The answer would be 0,3,8,15,24,35,48,63
Answer:
Step-by-step explanation:
3
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Rewrite in slope-intercept form.
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Using the slope-intercept form, the y-intercept is
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Tap for more steps...
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Using the slope-intercept form, the slope is
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