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7nadin3 [17]
3 years ago
9

I need help fast plz someone help I really need help an thank you

Mathematics
1 answer:
Valentin [98]3 years ago
3 0

Answer:

exact form: 26/3

decimal form: 8.6666...

mixed number form: 8 2/3

Step-by-step explanation:

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where p0 is the atmospheric pressure at sea level and k is a constant. If the atmospheric pressure is 14.7 lb/in.2 at sea level
balu736 [363]

Answer:

The value of pressure at an altitude of 10000 ft = 10 \frac{lb}{in^{2} }

Step-by-step explanation:

Given data

Atmospheric pressure P_{0} = 14.7 \frac{lb}{in^{2} }

Pressure at 4000 ft = 12.6 \frac{lb}{in^{2} }

If temperature is constant then the atmospheric pressure is varies with the altitude according to law

P (h) = P_{0} e^{- kh} ------ (1)

where k= constant & h = height

12.6 = 14.7 e^{- 4000k}

0.857 = e^{- 4000k}

㏑ 0.857 = - 4000 k

-0.154 = - 4000 k

k = 3.85 × 10^{-5}

Thus the atmospheric pressure at an altitude of 10,000 ft is

P_{10000} = 14.7 × e^{- kh} ----- (2)

Product of k & h is

k h = 3.85 × 10^{-5} × 10000

k h = 0.385

Put his value of k h = 0.385  in equation (2) we get

P_{10000} = 14.7 × e^{-0.385 }

P_{10000} = 10 \frac{lb}{in^{2} }

This is the value of pressure at an altitude of 10000 ft.

7 0
3 years ago
What are the answers to this? PLEASE HELP.
shepuryov [24]

Answer:

Ray : Line NA, Line NB, Line AB

Vertex : Vertex N

Angle: Angle ANB

Parallel Lines: None

Coplanar Points: Points C, A, F, N, B

Collinear Points: Points A, N, B

Segment Addition Postulate: AN + NB = AB

Perpendicular Lines: None

6 0
4 years ago
Which equation has no solution?
san4es73 [151]

Answer:

c

Step-by-step explanation:

hope this helps

4 0
3 years ago
Help please asappppppppp​
Aleonysh [2.5K]

Answer:

First Equation: 6a-23

Second Equation: 5a-20

Step-by-step explanation:

So, I think you want me to answer part 2...

For the first equation, we can see that the denominator stays the exact same, meaning the numerator will also not change.

For the second equation, we can see the denominator changed from a-3 to 5a-15. The denominator was simply multiplied by 5. Since the denominator was multiplied by five we must multiply the numerator by five as well.

5(a-4)

5a-20

Hope this helps :)

3 0
3 years ago
which of the following expresses the coordinates of the foci of the conic section shown below? (x-2)^2/4+(y+5)^2/9
elena55 [62]

Step-by-step explanation:

\frac{(x - 2) {}^{2} }{4}  +  \frac{(y + 5) {}^{2} }{9}  = 1

This is the equation of the ellipse. Since the denominator is greater for the y values, we have a vertical ellipse. Remember a>b, so a

The formula for the foci of the vertical ellipse is

(h,k+c) and (h,k-c).

where c is

Our center (h,k) is (2, -5)

{c}^{2}  =  {a}^{2}  -  {b}^{2}

Here a^2 is 9, b^2 is 4.

{c}^{2}  = 9 - 4

{c}^{2}  = 5

c =  \sqrt{5}

So our foci is

(2, - 5 +  \sqrt{5} )

and

(2, - 5 -  \sqrt{5} )

6 0
2 years ago
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