Multiply 400 times 0.70 and that’s how you get the % (in this case 280)
Answer:
Class Boundary = 1 between the sixth and seventh classes.
Step-by-step explanation:
Lengths (mm) Frequency
1. 140 - 143 1
2. 144 - 147 16
3. 148 - 151 71
4. 152 - 155 108
5. 156 - 159 83
6. 160 - 163 18
7. 164 - 167 3
The class boundary between two classes is the numerical value between the starting value of the higher class, which is 164 for the 7th class in this case, and the ending value of the class of the lower class, which is 163 for the 6th class in this case.
Therefore the class boundary between the sixth and seventh classes
= 164 - 163 = 1
Therefore Class Boundary = 1.
It can be seen that class boundary for the frequency distribution is 1.
If we take the difference between the lower limits of one class and the lower limit of the next class then we will get the class width value.
Therefore, Class width,
w = lower limit of second class - lower limit of first class
= 144 - 140
= 4
The others don’t make any sense so it has to be “A”.
Answer: The measurement of angle DBC is 65 degrees
Step-by-step explanation:
Line BD splits ABC into two angles ABD and DBC.
If ABC is 90 then the measures of ABD + DBC will be 90. Since we know the measure of ABD we can make this equation and solve it
Answer:
A.b = 210 + 15x
B.b = 210 – 15x
C.b = 195 + 15x
D.b = 195 – 15x
Step-by-step explanation
B is correct. Your starting amount is 210$ And you're taking away 15$ each time she uses the club,x.
