Wish i was smart enough to answer
As the pen is a triangle, the third side can either be the hypotenuse or a regular side. If the third side is the hypotenuse, it's length would be
![l= \sqrt{8^2+15^2} = \sqrt{64+225} = \sqrt{289} =17](https://tex.z-dn.net/?f=l%3D%20%5Csqrt%7B8%5E2%2B15%5E2%7D%20%3D%20%5Csqrt%7B64%2B225%7D%20%3D%20%5Csqrt%7B289%7D%20%3D17)
feet. If the third side is a regular side, than it would be
![l= \sqrt{15^2-8^2} = \sqrt{225-64} = \sqrt{161}](https://tex.z-dn.net/?f=l%3D%20%5Csqrt%7B15%5E2-8%5E2%7D%20%3D%20%5Csqrt%7B225-64%7D%20%3D%20%5Csqrt%7B161%7D)
≈12.689 feet. This means your third side can either be 17 feet long or 12.689 feet long.
Step-by-step explanation:
Area =0.5×base×height
Area= 0.5×5×3=7.5ft
The fraction would be 37 out of 42. You basically divide the two and get something around 88%.