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kotegsom [21]
1 year ago
11

Which of the options below does the month-end review process help with? Select all that apply.

Mathematics
2 answers:
Kitty [74]1 year ago
6 0

The option first, option third, option fifth, and option sixth are correct these all help with the month-end review process.

<h3>What is the month-end review process?</h3>

Making sure the books are accurate and complete is only one aspect of the month-end review procedure. It also involves assisting clients in locating and resolving problems that have an effect on the health of their businesses.

We have a statement:

Which of the options below does the month-end review process help with?

As we know, the month-end review process helps with the following options:

  • Finding transactions with outstanding issues
  • Dealing with unreconciled accounts
  • Identifying discrepancies with accounts and starting balances
  • Creating and sending management reports.

Thus, the option first, option third, option fifth, and option sixth are correct these all help with the month-end review process.

Learn more about the month-end review process here:

brainly.com/question/20596966

#SPJ1

Shkiper50 [21]1 year ago
4 0

The month-end review process help with the following below:

  • Finding transactions with outstanding issues.
  • Dealing with unreconciled accounts.
  • Running payroll.
  • Identifying discrepancies with accounts and starting balances.

<h3>What is Month-end review process?</h3>

This is usually done by the accounting department of an organization and are involved in payrolling.

Outstanding transactions and accounts are also reviewed so as to ensure accuracy.

Read more about Month-end review process here brainly.com/question/24134045

#SPJ1

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If sin A = 3/8, find the value of cosec A - sec A.​
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\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}

Step by step explanation:

\text{Given that,}\\\\~~~~~~\sin A = \dfrac 38 \\\\\implies \sin^2 A = \dfrac 9{64}\\\\\implies  1 - \cos^2 A = \dfrac{9}{64}\\\\\implies \cos ^2 A = 1 - \dfrac 9{64}\\\\\implies \cos^2 A = \dfrac{55}{64}\\\\\implies \cos A =\pm\sqrt{\dfrac{55}{64}}\\ \\\implies \cos A = \pm\dfrac{\sqrt{55}}8\\\\

\implies \dfrac 1{\cos A} = \pm\dfrac{8}{\sqrt{55}}

\text{Now,}\\\\\csc A - \sec A\\\\=\dfrac{1}{\sin A}- \dfrac{1}{\cos A}\\\\=\dfrac 83 -\left(\pm \dfrac 8{\sqrt {55}} \right)\\ \\\text{Hence,}\\\\\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}

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