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irga5000 [103]
2 years ago
10

-25-2-15--03₂- 051 152 25

Mathematics
1 answer:
Wewaii [24]2 years ago
7 0

Answer:

6377828

Step-by-step explanation:

7738828uiiekldfnnf

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Ronald scores 700 on the math section of the SAT exam. The distribution of SAT scores is approximately normal with a mean of 500
Artist 52 [7]

Answer:

a) Due to the higher z-score, Ronald performed better relative to his peers on the test.

b) Ronald needed a grade of at least 732.5, and Rubin of at least 33.58.

c) 95% of the population fall between graded of 4.868 and 31.132 on the ACT.

95% of the population fall between graded of 304 and 696 on the SAT.

Step-by-step explanation:

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

(a) Relative to their peers who also took the tests, who performed better on his test? Explain.

We have to find whoever has the higher z-score.

Ronald:

Ronald scores 700 on the math section of the SAT exam. The distribution of SAT scores is approximately normal with a mean of 500 and a standard deviation of 100. So the z-score is found when X = 700, \mu = 500, \sigma = 100. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{700 - 500}{100}

Z = 2

Rubin:

Rubin takes the ACT math exam and scores 31 on the math portion. ACT scores are approximately normally distributed with a mean of 18 and a standard deviation of 6.7. So the z-score is found when X = 31, \mu = 18, \sigma = 6.7. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{31 - 18}{6.7}

Z = 1.94

Due to the higher z-score, Ronald performed better relative to his peers on the test.

(b) A certain school will only consider those students who score in the top 1% in the math section. What grades would Ronald and Rubin have to receive on their respective tests to be considered for admission?

They have to be in the 100 - 1 = 99th percentile, that is, they need a z-score with a pvalue of at least 0.99. So we need to find for them X when Z = 2.325.

Ronald:

Z = \frac{X - \mu}{\sigma}

2.325 = \frac{X - 500}{100}

X - 500 = 232.5

X = 732.5

Rubin:

Z = \frac{X - \mu}{\sigma}

2.325 = \frac{X - 18}{6.7}

X - 18 = 15.58

X = 33.58

Ronald needed a grade of at least 732.5, and Rubin of at least 33.58.

(c) Between what two grades does 95% of the population fall for the ACT and the SAT exams?

They fall between the 100 - (95/2) = 2.5th percentile and the 100 + (95/2) = 97.5th percentile, that is, they fall between X when Z = -1.96 and X when Z = 1.96.

ACT:

Lower bound:

Z = \frac{X - \mu}{\sigma}

-1.96 = \frac{X - 18}{6.7}

X - 18 = -1.96*6.7

X = 4.868

Upper bound:

Z = \frac{X - \mu}{\sigma}

1.96 = \frac{X - 18}{6.7}

X - 18 = 1.96*6.7

X = 31.132

95% of the population fall between graded of 4.868 and 31.132 on the ACT.

SAT:

Lower bound:

Z = \frac{X - \mu}{\sigma}

-1.96 = \frac{X - 500}{100}

X - 500 = -196

X = 304

Upper bound:

Z = \frac{X - \mu}{\sigma}

1.96 = \frac{X - 500}{100}

X - 500 = 196

X = 696

95% of the population fall between graded of 304 and 696 on the SAT.

7 0
3 years ago
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