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valina [46]
2 years ago
8

Presently, Victor is three times as old as Maria. Ten years ago, Victor was seven times as old as Maria. How old is each person

now?
Mathematics
1 answer:
umka21 [38]2 years ago
7 0

Step-by-step explanation:

v = Victor's age

m = Maria's age

v = 3m

v - 10 = 7(m - 10)

3m - 10 = 7m - 70

60 = 4m

m = 15

v = 3m = 3×15 = 45

Victor is 45 years old. Maria is 15 years old.

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I need help writing the first 5 terms of the sequence!
Angelina_Jolie [31]

The first five terms of the sequence are 1, 4, 7, 10, 13.

Solution:

Given data:

a_{1}=1

a_{n}=a_{n-1}+3

General term of the arithmetic sequence.

a_{n}=a_{n-1}+d, where d is the common difference.

d = 3

a_{n}=a_{n-1}+3

Put n = 2 in a_{n}=a_{n-1}+3, we get

a_{2}=a_1+3

a_{2}=1+3

a_2=4

Put n = 3 in a_{n}=a_{n-1}+3, we get

a_{3}=a_2+3

a_{3}=4+3

a_3=7

Put n = 4 in a_{n}=a_{n-1}+3, we get

a_{4}=a_3+3

a_{4}=7+3

a_4=10

Put n = 5 in a_{n}=a_{n-1}+3, we get

a_{5}=a_4+3

a_{5}=10+3

a_5=13

The first five terms of the sequence are 1, 4, 7, 10, 13.

3 0
3 years ago
1/3x * 6 = -8<br><br> it says solve
bulgar [2K]

Subtract 6 from both sides, you get 1/3x=-14

Now multiply both sides by there, hence x=-42

6 0
3 years ago
Read 2 more answers
544484454545454c454545x454544d5454d5w4ds5d45x45a45s4544444444444444444444444444444444444444449999999999999999xx599999999999994x5
MAXImum [283]

Answer:

uh. the answer to this is

8 0
2 years ago
Read 2 more answers
I don't understand any of these questions
Xelga [282]
20 because there are many more
6 0
3 years ago
Read 2 more answers
A box is x to inches high,(2x+3)inches wide, and (2x+5) of inches long. In terms of x, what is the volume (v) of the box?
Advocard [28]

Answer:

The volume of the box is V=(4x^3+16x^2+15x)\ in^3

Step-by-step explanation:

we know that

The volume of the box is equal to

V=LWH

where

L is the length of the box in inches

W is the width of the box in inches

H is the height of the box in inches

we have

L=(2x+5)\ in\\W=(2x+3)\ in\\H=x\ in

substitute in the formula

V=(2x+5)(2x+3)x

V=(4x^2+6x+10x+15)(x)

V=(4x^2+16x+15)(x)

V=(4x^3+16x^2+15x)\ in^3

6 0
3 years ago
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