Lines and triangles practices
1 answer:
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Answer:
Step-by-step explanation:
Universal set
U = 500
The number that likes snickers
n(S) = 42
The number that like Twix.
n(T) = 110
The number that like Reeses
n(R) = 125
n(S n T) = 33
n(T n R) = 62
n(S n R) = 26
n( S n R n T) = 22
Then,
n(S n T) only = n(S n T) - n(S n R n T)
n(S n T) only =33 - 22 = 11
n(T n R) only = n(T n R) - n(S n R n T)
n(T n R) only =62 - 22 = 40
n(S n R) only = n(S n R) - n(S n R n T)
n(S n R) only =26 - 22 = 4.
Also,
n(S) only = n(S) - n(S n R) - n(S n T) only
n(S) only = 42 - 26 - 11 = 5
n(T) only = n(T) - n(T n R) - n(T n S) only
n(T) only = 110 - 62 - 11 = 37
n(R) only = n(R) - n(S n R) - n(R n T) only
n(R) only = 124 - 26 - 40 = 58
Then, to know if some student don't like any of the of chocolate,
Let know the number of students that like the chocolate candy
n(S) + n(T)only + n(T n R)only + n(R) only
42 + 37 + 40 + 58 = 177 students.
Therefore, the total students that like chocolate candy is 177, so those that does not like any of them are
n(S U R U T)' = U – n(S U R U T)
n(S U R U T) = 500 - 177 = 323.
So, the question is how many student likes at most 2 kinds of these chocolates, this means that they can like exactly 2 or less or even none.
So, this category are
n(2 most) = n(S n T)only + n(R n T)only + n(S n R)only + n(s)only + n(T)only + n(R)only + n(S U R U T)'
n(2 most) = 11 + 40 + 4 + 5 + 37 + 58 + 323
n(2 most) = 478
The correct answer is E.
Check attachment for Venn diagram
Answer:
A bit of a doosy, but bare with me: f*g*h(x) =
Step-by-step explanation:
So explaining this is a bit awkward as well, but I can try...So
Starting from g(x) working that backwards into f(x), so...
g(x) =
f(x) =
Take your g(x) and plug it into your f(x) into every x you see
f(g(x)) = ~ I hope you can visualize this, but do you see how g(x) plugs into f(x)...
Now you still have one more step which you still need to include h(x), so
Remember h(x) =
Now plug in your h(x) into every x you see from f(g(x)) and it should look like...