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2 years ago

Identify the center and radius of the circle with the following equation: 〖(x+3)〗^2+〖(y-1)〗^2=81

Mathematics

1 answer:

kirill115 [55]2 years ago

4 0

Answer:

centre (3 ,-1) , r=9

Explanation:

The standard form of the equation of a circle is.

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

(

−

)

(

−

)

∣

−−−−−−−−−−−−−−−−−−−−−−−−−

where (a,b) are the coordinates of the center and r , the radius.

For the given equation: a = 3 , b = -1 and r = 9

hence centre = (3 ,-1) and radius = 9

Step-by-step explanation:

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Given that f(x) = 2x − 5, find the value of x that makes f(x) = 15.

Vladimir79 [104]

Answer:

Step-by-step explanation:

so you replace all the x's with 15 and it becomes

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Una persona camina 7 kilómetros hacia el norte, después 3 kilómetros hacia el este y, luego, 3 kilómetros hacia el sur. ¿A qué d

qaws [65]

Answer:

La persona está a 5 kilómetros con respecto al punto de partida.

Step-by-step explanation:

Considérese que la dirección norte coincide con el semieje +y y que la dirección este coincide con el semieje +x. A continuación, obtenemos las formas vectoriales equivalentes de cada afirmación:

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$\vec r_{1} = 7\,\hat{j}\,[km]$

(ii) Después 3 kilómetros hacia el este:

$\vec r_{2} = 3\,\hat{i}\,[km]$

(iii) Y luego, 3 kilómetros hacia el sur:

$\vec r_{3} = -3\,\hat{j}\,[km]$

El vector resultante de desplazamiento se construye a partir de la siguiente suma de vectores:

$\vec R = \vec r_{1}+\vec r_{2} + \vec r_{3}$ (1)

$\vec R = 3\,\hat{i} + 4\,\hat{j}\,[km]$

Asumiendo que la distancia coincide con el desplazamiento resultante, calculamos la distancia con respecto al punto de partida mediante el Teorema de Pitágoras:

$\|\vec R\| = \sqrt{3^{2}+4^{2}}$

$\|\vec R\| = 5\,km$

La persona está a 5 kilómetros con respecto al punto de partida.

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