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scoray [572]
2 years ago
7

Identify the center and radius of the circle with the following equation: 〖(x+3)〗^2+〖(y-1)〗^2=81

Mathematics
1 answer:
kirill115 [55]2 years ago
4 0

Answer:

centre (3 ,-1) , r=9

Explanation:

The standard form of the equation of a circle is.

∣

∣

∣

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

(

x

−

a

)

2

+

(

y

−

b

)

2

=

r

2

a

a

∣

∣

−−−−−−−−−−−−−−−−−−−−−−−−−

where (a,b) are the coordinates of the center and r , the radius.

For the given equation: a = 3 , b = -1 and r = 9

hence centre = (3 ,-1) and radius = 9

Step-by-step explanation:

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The following week, clare earns $75 from delivering newspapers and deposits it in her account. What will her account balance be
dezoksy [38]

Answer: Whatever the original balance was + 75

Step-by-step explanation:

You never gave a concrete value of what the balance of her account was before the new deposit so it is impossible for me to tell you the exact answer, but just add $75 to whatever it was before and you will be correct!  If you tell me the original value I would be more than happy to help you further :)  Have a great rest of your day!

6 0
2 years ago
Line m passes through the points (-2,7) and (4,-5), as shown below. Which of the following could be the equation of a line that
True [87]

Slope-intercept form:  y = mx + b

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

For lines to be parallel, they need to have the same slope.

To find the slope (m), use the slope formula:

m=\frac{y_2-y_1}{x_2-x_1}      And plug in the two points

(-2, 7) = (x₁, y₁)

(4, -5) = (x₂, y₂)

m=\frac{y_2-y_1}{x_2-x_1}

m=\frac{-5-7}{4-(-2)}   (two negative signs cancel each other out and become positive)

m=\frac{-5-7}{4+2}

m=\frac{-12}{6}     Simplify the fraction

m = -2        

The slope is -2, so the parallel line's slope is also -2.

Your answer is C

3 0
3 years ago
The area of a bulletin board is 55 ft2. The length is nine feet less than four times the width. Find the length and the width, i
galben [10]

Answer:

The length and width are 11ft and 5ft respectively

Step-by-step explanation:

let the

length = L

Width = W

Area = LW = 55

The length is nine feet less than four times the width

L = 4W - 9

W (4W - 9) = 55

4W^2 - 9W -55 = 0

4W^2 - 20W + 11W - 55 = 0

4W(W - 5) + 11(W - 5) = 0

(W - 5)(4W + 11) = 0

W - 5 = 0 , 4W + 11=0

W = 5 or  - 11/4

since the width cannot be negative, W = 5

LW = 55

L = 55/5

L = 11

The length and width are 11ft and 5ft respectively.

7 0
3 years ago
Identify the equation in slope-intercept for for the line containing the point (-3,5) and patella to y = -2/3x+5/3
Olegator [25]

Answer:

Y = - 2/3 x + 3

Step-by-step explanation:

y = -2/3x+5/3

Slope = -2/3. .. parallel line has same slope

For (- 3 , 5)

Y intercept = y - my = 5 - ( (-2/3) x (-3) ) = 3

Y = slope x X + y intercept

Y = - 2/3 x + 3

8 0
3 years ago
Solve. 4x−y−2z=−8 −2x+4z=−4 x+2y=6 Enter your answer, in the form (x,y,z), in the boxes in simplest terms. x= y= z=
ladessa [460]

Answer:

(-2, 4, -2)

x=-2, y=4, z=-2.

Step-by-step explanation:

So we have the three equations:

4x-y-2z=-8\\-2x+4z=-4\\x+2y=6

And we want to find the value of each variable.

To solve this system, first look at it and consider what you should try to do.

So we can see that the second and third equations both have an x.

Therefore, we can isolate the variables for the second and third equation and then substitute them into the first equation to make the first equation all xs.

Therefore, let's first isolate the variable in the second and third equation.

Second Equation:

-2x+4z=-4

First, divide everything by -2 to simplify things:

x-2z=2

Subtract x from both sides. The xs on the left cancel:

(x-2z)-x=2-x\\-2z=2-x

Now, divide everything by -2 to isolate the z:

z=-\frac{2-x}{2}

So we've isolated the z variable. Now, do the same to the y variable in the third equation:

x+2y=6

Subtract x from both sides:

2y=6-x

Divide both sides by 2:

y=\frac{6-x}{2}

Now that we've isolated the y and z variables, plug them back into the first equation. Therefore:

4x-y-2z=-8\\4x-(\frac{6-x}{2})-2(-\frac{2-x}{2})=-8

Distribute the third term. The -2s cancel out:

4x-(\frac{6-x}{2})+(2-x)=-8

Since there is still a fraction, multiply everything by 2 to remove it:

2(4x-(\frac{6-x}{2})+(2-x))=2(-8)

Distribute:

8x-(6-x)+2(2-x)=-16\\8x-6+x+4-2x=-16

Combine like terms:

8x+x-2x-6+4=-16\\7x-2=-16

Add 2 to both sides:

7x=-14

Divide both sides by 7:

(7x)/7=(-14)/7\\x=-2

Therefore, x is -2.

Now, plug this back into the second and third simplified equations to get the other values.

Second equation:

z=-\frac{2-x}{2}\\ z=-\frac{2-(-2)}{2}\\z=-\frac{4}{2}\\z=-2

Third equation:

y=\frac{6-x}{2}\\y=\frac{6-(-2)}{2}\\y=\frac{8}{2}\\y=4

Therefore, the solution is (-2, 4, -2)

3 0
3 years ago
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