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Fudgin [204]
3 years ago
10

Need help with this math question

Mathematics
1 answer:
Hoochie [10]3 years ago
4 0

Answer:

x = 3.1 ft

Step-by-step explanation:

Use Pythagoras' Theorem to find the base of the triangle. The base of the triangle is half of 'x'. Let's call the base 'y' for now.

To find 'y' we must use this formula,

y^{2} = c^{2} -b^{2}

'c' is the hypotenuse, the longer side, and 'b' is the other short side.

Sub in the numbers for 'c' and 'b',

y^{2} = 2.1^{2} -1.4^{2}

               = 2.45

Square root both sides to get 'y' by itself,

y = 1.5652.....

Remember that 'y' is half of x? Simply multiply 'y' by 2 to get an answer for 'x',

x = 1.5652.... x 2

  = 3.1 ft (1 d.p. nearest tenth)

Hope this helped!!

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Answer: -$266

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When a number is added to 1/5 of itself, the result is 24. The equation that models this problem is n + 1/5n = 24. What is the v
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The answer is 20 since 1/5 of 20 is 4, and 20 + 4 = 24.
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3 years ago
Read 2 more answers
Please help asap!!!
sp2606 [1]

Answer:

y=\frac{1}{6} (x+5)^2-4.5

y=\frac{-1}{20} (x-10)^2+1

Step-by-step explanation:

focus at (-5, -3), and directrix y = -6

Directrix y=-6 so its  a vertical parabola

so equation is

(x-h)^2 = 4p(y-k)

(h,k) is the center

P is the distance between focus and vertex

distance between focus and directrix = 2p

distance between -3  and y=-6 is 3

2p = 3

p = 3/2 or p = 1.5

Focus is (h, k+p)

given focus is (-5, -3) so h= -5  and k+p = -3

k+p=-3, plug in 1.5 for p

k + 1.5 = -3

subtract 1.5 on both sides

k = -4.5

(x-h)^2 = 4p(y-k)

(x+5)^2= 4(1.5) (y+4.5)

(x+5)^2= 6(y+4.5)

divide by 6 on both sides

then subtract 4.5 on both sides

y=\frac{1}{6} (x+5)^2-4.5

focus at (10, -4), and directrix y = 6.

Directrix y=6 so its  a vertical parabola

so equation is

(x-h)^2 = 4p(y-k)

distance between focus and directrix = 2p

distance between -4  and y=6 is -4-6=-10

2p = -10

p = -5

Focus is (h, k+p)

given focus is (10, -4) so h= 10  and k+p = -4

k+p=-4, plug in 5 for p

k - 5 = -4

add 5 on both sides

k = 1

(x-h)^2 = 4p(y-k)

(x-10)^2= 4(-5) (y-1)

(x-10)^2= -20(y-1)

divide by -20 on both sides and add 1 on both sides

y=\frac{-1}{20} (x-10)^2+1


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