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3 years ago

Find the area of a triangle if the base is 8.2 m and the height is 4.6 m. (A=1/2bh)

Mathematics

2 answers:

jenyasd209 [6]3 years ago

8 0

Answer:

18.86

Step-by-step solution:

8.2 * 4.6 = 37.72

divide by two, 18.86

Sorry I couldn't elaborate further, I'm really busy right now. Please contact me if you need any more help and I will be sure to help you more soon.

Tcecarenko [31]3 years ago

5 0

Answer:

18.86

Step-by-step explanation:

8.2 x 4.6 = 37.72

37.72/2 = 18.86

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Question 10 (7 points) d Elizabeth borrowed $20,000 for five years at a 5% annual interest rate, what is her monthly payment, to

zhenek [66]

Answer:

monthly payment is $377

C is the correct option.

Step-by-step explanation:

The formula for the monthly payment is given by

$C=\frac{Prt(1+r)^n}{(1+r)^n-1}$

Given that,

P = $20,000

n = 5 years = 60 months

r = 0.05

Substituting these values in the formula

$C=\frac{20000\cdot \frac{0.05}{12}(1+\frac{0.05}{12})^{60}}{(1+\frac{0.05}{12})^{60}-1}$

On simplifying, we get

$C=\$377.425\\\\C\approx \$377$

Therefore, the monthly payment is $377

C is the correct option.

4 0

3 years ago

I need the x intercepts for (x+3)(x + 7) = 0

Scrat [10]

Answer:

-3, -7

Step-by-step explanation:

either x + 3 = 0 --> x = -3

or x + 7 = 0 --> x = -7

3 0

3 years ago

Read 2 more answers

The computer center at Dong-A University has been experiencing computer down time. Let us assume that the trials of an associate

Schach [20]

Answer:

(a)0.16

(b)0.588

Step-by-step explanation:

The matrix below shows the transition probabilities of the state of the system.

$\left(\begin{array}{c|cc}&$Running&$Down\\---&---&---\\$Running&0.90&0.10\\$Down&0.30&0.70\end{array}\right)$

(a)To determine the probability of the system being down or running after any k hours, we determine the kth state matrix $P^k$ .

(a)

$P^1=\left(\begin{array}{c|cc}&$Running&$Down\\---&---&---\\$Running&0.90&0.10\\$Down&0.30&0.70\end{array}\right)$

$P^2=\begin{pmatrix}0.84&0.16\\ 0.48&0.52\end{pmatrix}$

If the system is initially running, the probability of the system being down in the next hour of operation is the $(a_{12})th$ entry of the P^2$ matrix.$

The probability of the system being down in the next hour of operation = 0.16

(b)After two(periods) hours, the transition matrix is:

$P^3=\begin{pmatrix}0.804&0.196\\ 0.588&0.412\end{pmatrix}$

Therefore, the probability that a system initially in the down-state is running

is 0.588.

(c)The steady-state probability of a Markov Chain is a matrix S such that SP=S.

Since we have two states, $S=[s_1$ s_2]$

$[s_1$ s_2]\left(\begin{array}{ccc}0.90&0.10\\0.30&0.70\end{array}\right)=[s_1$ s_2]$

Using a calculator to raise matrix P to large numbers, we find that the value of $P^k$ approaches [0.75 0.25]:

Furthermore,

$[0.75$ 0.25]\left(\begin{array}{ccc}0.90&0.10\\0.30&0.70\end{array}\right)=[0.75$ 0.25]$

The steady-state probabilities of the system being in the running state and in the down-state is therefore:

$[s_1$ s_2]=[0.75$ 0.25]$

4 0

4 years ago

Solve for v:<br> 5(5v + 4) = 17v + 8v+ 9 + 9 <br><br> Omg Pleasssee Help Me

Natali5045456 [20]

Answer:

5(5v+4)=17v+8v+9+9

25v+20=25v+18

25v-25v=18-20

0v=-2

i think soooo

this question is very very irrelevant

Step-by-step explanation:

8 0

3 years ago

1. Demonstrate the validity of the following identities by means of truth tables: (5 pts each) a. DeMorgan’s theorm for three va

ollegr [7]

Answer:

All the three statements presented are indeed valid and satisfy the De Morgan's theorem.

Step-by-step explanation:

The truth tables are presented in the attached images.

a) The statement (X + Y + Z)' = (X'Y'Z') has its proof in the first image attached.

b) The statement (XYZ)' = (X' + Y' + Z') has its proof in the second image attached.

c) The statement (X + YZ) = (X + Y)(X + Z) has its proof in the third image attached.

3 0

4 years ago