Answer:
1,215 Superscript one-fifth x
Step-by-step explanation:
Given:
The expression to simplify is given as:
![(\sqrt[5]{1215})^x](https://tex.z-dn.net/?f=%28%5Csqrt%5B5%5D%7B1215%7D%29%5Ex)
We know that,
![\sqrt[n]{a} = a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%20%3D%20a%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
Here, 
So, ![\sqrt[5]{1215} = 1215^{\frac{1}{5}}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B1215%7D%20%3D%201215%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D)
So, the above expression becomes:
Now, using the law of indices 
Here, 
So, the expression is finally simplified to;

Therefore, the second option is the correct one.
= 1,215 Superscript one-fifth x
Answer:

Step-by-step explanation:

Use the distributive property for 2(x + 1).

Subtract 2x from 5x.

Bring 2 to the right hand side of the equation .

Add 1/4 & 2.
![3x = \frac{1}{4} + \frac{8}{4} \: \: [LCM = 4]\\3x = \frac{9}{4}](https://tex.z-dn.net/?f=3x%20%3D%20%5Cfrac%7B1%7D%7B4%7D%20%2B%20%5Cfrac%7B8%7D%7B4%7D%20%5C%3A%20%5C%3A%20%5BLCM%20%3D%204%5D%5C%5C3x%20%3D%20%5Cfrac%7B9%7D%7B4%7D)
Now, bring 3 to the right hand side of the equation .
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Answer:
Top right graph.
Step-by-step explanation:
The graph of f(x) = x has a slope of 1, and is increasing to the right until the point where x = -1.
The graph of f(x) = -x has a slope of -1 decreasing to the right from the point where x = -1.
The clear small circle means that the point is not included in the function ( because of the '<' ).
The filled circle means it is included ( the '≥').