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Shtirlitz [24]
2 years ago
6

At a certain college, 49% of the students are female, and 21% of the students major in civil engineering. Furthermore, 8% of the

students both are female and major in civil engineering.
Mathematics
1 answer:
Alla [95]2 years ago
8 0

The probability that a student is a female or major in civil engineering is 62%

<h3>How to determine the probability?</h3>

Let A represent Female and B represents civil engineering.

So, we have:

P(A) = 49%

P(B) = 21%

P(A and B) = 8%

The required probability is calculated as:

P(A or B) = P(A) + P(B) - P(A and B)

This gives

P(A or B) = 49% + 21% - 8%

Evaluate

P(A or B) = 62%

Hence, the probability that a student is a female or major in civil engineering is 62%

<h3>Complete question</h3>

At a certain college, 49% of the students are female, and 21% of the students major in civil engineering. Furthermore, 8% of the students both are female and major in civil engineering. What is the probability that a randomly selected female student majors in civil engineering?

Read more about probability at:

brainly.com/question/251701

#SPJ1

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erastova [34]

Answer:

The probability is \frac{56!}{64!}

Step-by-step explanation:

We can divide the amount of favourable cases by the total amount of cases.

The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8, 64 \choose 8 .

For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function  f : A \rightarrow A , with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.

Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.

We can conclude that the probability for 8 rooks not being able to capture themselves is

\frac{8!}{64 \choose 8} = \frac{8!}{\frac{64!}{8!56!}} = \frac{56!}{64!}

7 0
3 years ago
What is the answer to 7+6y &gt;19 ?
goldenfox [79]

Answer:

y>2

\{y\in \mathbb{R}|y>2\}

The interval notation is: (2, \infty)

Step-by-step explanation:

7+6y>19

6y>12

y>2

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3 years ago
Does anyone know all the concepts/rules needed to learn math in college? I want to make sure I have things I need now in my seni
Mandarinka [93]

Answer:

Basic college math topics include whole numbers, fractions, numbers, decimals and integers. Problem solving, algebra, percents and geometry are also included in course content.

Step-by-step explanation:

5 0
2 years ago
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Give EG = 5x+7 EF =5x and FG=2x-7
Len [333]

Answer:

x = 7

42, 35, 7

Step-by-step explanation:

  • EG = 5x+7
  • EF = 5x  
  • FG = 2x-7

Point F is on line segment of EG, therefore EG = EF + FG

  • 5x + 7 = 5x + 2x - 7
  • 2x = 14
  • x = 7

Then

  • EG = 5*7 + 7 = 42
  • EF = 5*7 = 35
  • FG = 2*7 - 7 = 7
7 0
3 years ago
A planter box can hold 3, ft of soil. The area of the base of the box is 24 ft. A sketch of the box is shown.
liraira [26]

Answer:

8

24 divided by 3= 8  

8x3=24 ft

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3 years ago
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