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Ghella [55]
2 years ago
8

Find the slope of the line that passes through (9,-3) and (9,-8)

Mathematics
1 answer:
miskamm [114]2 years ago
7 0

Answer:

The line has no slope. I hope this helps

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Find the length of the hypothenuse of the right triangle with legs that measure 5 and 7. Brianlest for anyone who can give step
zepelin [54]
To calculate hypothenuse you use the formula a^2+b^2=c^2 where c is the length of the hypothenuse.

1. 5^2+7^2=c^2
2.25+49=74
3. Now you will square root the 74
4. The hypothenuse is equal to 8.6
4 0
3 years ago
Write the equation in slope-intercept form. 5x+3y=12
Umnica [9.8K]
5x+3y=12
Subtract 5x from both sides
3y=-5x+12
Divide by 3
Y=-5/3x +4
7 0
3 years ago
What is the distance between (−5,−4) and (-6,4)?
Helga [31]

The distance formula is:  d  =  sqrt( (x2 - x1)2 + (y2 - y1)2 )

 

For this problem, let (-5, -4) be the "first" point, so  x1 = -5  and  y2 = -4

                      and let (-6, 4) be the "second" point, so  x2 = -6  and  y2 = 4.

 

Then:  d  =  sqrt( (-6 - -5)2 + (4 - -4)2 )  =  sqrt( (-1)2 + (8)2 )  =  sqrt( 1 + 64 )  =  sqrt( 65)

 

The distance formula is just the Pythagorean Theorem applied to an x-y graph.

 

You would get the same final answer if you let (-5, -4) be the second point and (-6, 4) be the first point.

6 0
3 years ago
If money in a savings account earned 8% interest per annum, how much nterest would be earned on $150.00 over three years?
Pani-rosa [81]

Answer:

$36

Step-by-step explanation:

Given :

Interest rate, r = 8% = 0.08

Principal, P = 150

Time, t = 3 years

Simple interest = (principal * rate * time)

Simple interest = (150 * 0.08 * 3)

Simple interest = $36

7 0
3 years ago
Find the missing dimension of the prism. Round your answer to the nearest hundredth.
Nitella [24]

Answer:

x = 6.99in

Step-by-step explanation:

Given

l =2in

Volume = 72.66in^3

See attachment for prism

Required

Find x

The prism has a regular hexagon base

The base area is calculated as:

Base\ Area= \frac{3\sqrt 3}{2}l^2

This gives:

Base\ Area= \frac{3\sqrt 3}{2} * 2^2

Base\ Area= \frac{3\sqrt 3}{2} * 4

Base\ Area= 3\sqrt 3 * 2

Base\ Area= 6\sqrt 3

Side x represents the height.

So, we have:

Volume = Base\ Area*x

Make x the subject

x = \frac{Volume }{ Base\ Area}

x = \frac{72.66in^3}{6\sqrt 3 in^2}

x = \frac{72.66}{6\sqrt 3}in

x = \frac{12.11}{\sqrt 3}in

x = 6.99in --- approximated

6 0
3 years ago
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