Find the range of allowable values based on an expected mass of 250 grams for which values are allowed to vary by 5%.
1 answer:
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Answer:
V = π /2 volume units
Step-by-step explanation:
Volume of y = √x bounded by y = x and y = 1
y = √x
limits of integration ( see Annex )
By simple inspection limits of integration are x = 0 to x = 1
or y = √x and y = x
solving these two equations
x = 0 y = 0 x = 1 y = ± 1
V = ∫ π*f(x)²*dx
V = π * ∫₀¹ x*dx = π * x²/2 |₀¹
V = π * (1/2) - 0
V = π /2 volume units
