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krok68 [10]
2 years ago
8

Find the value of x. Then find the angle measures of the polygon.

Mathematics
2 answers:
BartSMP [9]2 years ago
6 0

Answer: x = 35

Final answer: 40, 105, 35.  

Answer: x = 35

So, it would be  40, 3(35), and 35.

Final answer: 40, 105, 35.  

First, we know that sum of angle measure 180.

So, algebraically, we can put out this equation.

40 + 3x + x = 180

Now we solve

Step-by-step explanation:

Given: 40+ 3x + x = 180

The whole goal is to isolate x. Remember DCMAM: Distribute, combine, move variable to one side to another, add/subtract, divide/multiply

There is no distribution, so move on.

We do have to combine 3x with x

40 + 4x = 180.

Now move 40 to the right side.

40 + 4x = 180

-40            -40

4x =  140

Now divide 140 by four

4x/4 = 140/4

x = 35

So, it would be  40, 3(35), and 35.

Final answer: 40, 105, 35.

Hope this helps.

bogdanovich [222]2 years ago
4 0

Answer:

X=140/3

Step-by-step explanation:

180-40=140, 140 divided by 3 is 140/3, so 40+3x140/3=180

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3 years ago
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A square has an area of 9ft^2 what is the length,in feet of each of the square sides
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12

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5 0
3 years ago
What is the missing constant term in the perfect square that starts with x^2-12x
Ipatiy [6.2K]

Essentially, we are trying to find the missing constant term of (x - a)^2 (remember that we are subtracting a due to the negative sign in front of the second term). Let's expand this to see what we can work with:

(x - a)^2

  • Set up

x^2 - ax - ax + a^2 = x^2 - 2ax + a^2

  • FOIL and simplify

Now, we know the second term is 12x, so let's set the second term in the polynomial we just found equal to 12x:

2ax = 12x

  • Set up

2a = 12

  • Divide both sides of the equation by x

a = 6

  • Divide both sides of the equation by 2

We have found a = 6. We know the missing constant term is a^2, according to the polynomial we found earlier. Thus, the missing term is:

a^2 \Rightarrow 6^2 = 36


The missing constant term is 36.

4 0
3 years ago
if we write a 3 in front of a two-digit number, the new three digit number will be 24 more than 7 tines the origional two digit
JulsSmile [24]

Here we have a simple algebra problem, we will see that the original number was 46.

<h3>How to find the equation we need to solve:</h3>

We know that we start with a 2 digit number, it can be written as:

a*10 + b

Where a and b are decimal numbers. (from 0 to 9).

If we add a 3 "in front of it", we are adding:

3*100 + a*10 + b

And this is 24 more than 7 times the original number, so we have:

3*100 + a*10 + b = 24 + 7*(a*10 + b)

Now we can solve that:

300 + a*10 + b = 24 + a*70 + b*7

300 - 24 + a*10 - a*70 + b - b*7 = 0

276 - a*60 - b*6 = 0

276 = a*60 + b*6

This part is tricky, here you need to remember that a and b can only be integers from 0 to 9, so you can try with different integer values for b and see if a is also an integer for that value, for example taking b = 6 we get:

276 = a*60 + 6*6 = a*60 + 36

276 - 36 = a*60

240/60 = a = 4

So if b = 6, then a = 4, so both are integers in the wanted range.

From this, we can conclude that the original number is 46.

If you want to learn more about algebra, you can read:

brainly.com/question/4344214

4 0
3 years ago
Can someone help me please.
Katyanochek1 [597]
The first fraction is 7/10.
The second bag has the same probability as the top so just copy the fractions into the boxes.
To calculate the probability of the same colour being chosen you follow these steps.
P(RR) = 3/10 x 4/9 = 12/90
P(GG) = 7/10 x 5/9 = 35/90
Then add the two fractions.
12/90 + 35/90 = 47/90
The last box is 47/90.
5 0
3 years ago
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