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antoniya [11.8K]
2 years ago
6

1. Which graph describes the relation {(1, 2), (1, -2), (−1, 2), (-2, 0)}?

Mathematics
1 answer:
Leviafan [203]2 years ago
5 0

Answer:

The first graph

Step-by-step explanation:

The second graph does not have a point at (1, -2).

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Rewrite in simplest terms -5(3u + 1) + 10
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Answer:

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Step-by-step explanation:

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The position vector for a particle moving on a helix is
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Answer:

a) 25.15

b)

   x = 1

   y = t

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c) (x,y) = (1, -2pi)

Step-by-step explanation:

a)

First lets calculate the velocity, that is, the derivative of c(t) with respect to t:

v(t) = (-sin(t), cos(t), 2t)

The velocity at t0=4pi is:

v(4pi) = (0, 1, 8pi)

And the speed will be:

s(4pi) = √(0^2+1^2+ (8pi)^2) = 25.15

b)

The tangent line to c(t) at t0 = 4pi has the parametric form:

(x,y,z) = c(4pi) + t*v(4pi)

Since

 c(4pi) = (1, 0, (4pi)^2)

The tangent curve has the following components:

x = 1

y = t

z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)

c)

The intersection with the xy plane will occurr when z = 0

This happens at:

  t1 = -2pi

Therefore, the intersection will occur at:

(x,y) = (1, -2pi)

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D and F

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Answer:

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Step-by-step explanation:

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