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marysya [2.9K]
2 years ago
14

(x + 8/3)^2 + y^2 = 1 What is the center of the circle? what is the radius?

Mathematics
1 answer:
fiasKO [112]2 years ago
3 0

(x+8/3)²+y²=1

(x+8/3)²+y²+0²+2×0y=1

(x+8/3)²+(y+0)²=(V1)²

->center: C(8/3,0)

-> radius: V1

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A right triangle is graphed on a coordinate plane. Find the length of the hypotenuse. Round your answer to the nearest tenth. ​
Hoochie [10]

Answer:

7.6

Step-by-step explanation:

From the graph, we know the lengths of two legs.

  a = 3

  b = 7

Knowing this, we can use the Pythagorean Theorem to solve for c, the hypotenuse. (remember,  a^2 + b^2 = c^2)

c = √a2 + √b2  

= √(7)2 + √(3)2

= √49 + √9

= √58

= 7.6

8 0
3 years ago
Find the value of x. Round your answer to the nearest tenth
snow_tiger [21]

Answer:

64.01

Step-by-step explanation:

tan∅= p/b

tan58= x/40

or, x= 40×tan58

x = 64.01

6 0
3 years ago
Find the sum of the first 20 terms of an arithmetic sequence with an 18th term of 8.1 and a common difference of 0.25.
il63 [147K]

The sum of the first 20 terms of an arithmetic sequence with the 18th term of 8.1 and a common difference of 0.25 is 124.5

Given,

18th term of an arithmetic sequence = 8.1

Common difference = d = 0.25.

<h3>What is an arithmetic sequence?</h3>

The sequence in which the difference between the consecutive term is constant.

The nth term is denoted by:

a_n = a + ( n - 1 ) d

The sum of an arithmetic sequence:

S_n = n/2 [ 2a + ( n - 1 ) d ]

Find the 18th term of the sequence.

18th term = 8.1

d = 0.25

8.1 = a + ( 18 - 1 ) 0.25

8.1 = a + 17 x 0.25

8.1 = a + 4.25

a = 8.1 - 4.25

a = 3.85

Find the sum of 20 terms.

S_20 = 20 / 2 [ 2 x 3.85 + ( 20 - 1 ) 0.25 ]

         = 10 [ 7.7 + 19 x 0.25 ]

         = 10 [ 7.7 + 4.75 ]

         = 10 x 12.45

         = 124.5

Thus the sum of the first 20 terms of an arithmetic sequence with the 18th term of 8.1 and a common difference of 0.25 is 124.5

Learn more about arithmetic sequence here:

brainly.com/question/25749583

#SPJ1

8 0
1 year ago
Please find the slope
olga nikolaevna [1]
After using the slope formula your answer would be 5/0.1 but when simplifying your answer is 50
7 0
3 years ago
How many 10-digit ternary strings are there that contain exactly two 0s, three 1s, and five 2s?
Svet_ta [14]

There are \dbinom{10}2 ways of picking 2 of the 10 available positions for a 0. 8 positions remain.

There are \dbinom83 ways of picking 3 of the 8 available positions for a 1. 5 positions remain, but we're filling all of them with 2s, and there's \dbinom55=1 way of doing that.

So we have

\dbinom{10}2\dbinom83\dbinom55=\dfrac{10!}{2!(10-2)!}\dfrac{8!}{3!(8-3)!}\dfrac{5!}{5!(5-5)!}=2520

The last expression has a more compact form in terms of the so-called multinomial coefficient,

\dbinom{10}{2,3,5}=\dfrac{10!}{2!3!5!}=2520

5 0
3 years ago
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