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kifflom [539]
1 year ago
9

Triangle abc is located on a coordinate plane angle c is at (1,2) the triangle is rotated counter clockwise 90° about the origin

enter coordinates for c’
Mathematics
1 answer:
sertanlavr [38]1 year ago
6 0

After rotating a point C 90° counterclockwise about the origin the coordinates of C' would be (-2, 1)

In this question, we have been given a triangle ABC.

A point C is at (1, 2)

The triangle is rotated counter clockwise 90° about the origin.

We need to find the coordinates of C' which is image of vertex C  after rotation.

We know that, if we rotate a point 90° counterclockwise about the origin a point (x, y) becomes (-y, x).

Here C(1, 2) is rotated 90 degrees counterclockwise about the origin.

So, the coordinates of C' would be,

C' = (-2, 1)

Therefore, after rotating a point C 90° counterclockwise about the origin the coordinates of C' are (-2, 1)

Learn more about the rotation here:

brainly.com/question/2763408

#SPJ1

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3 years ago
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melamori03 [73]
Sin 45° = opposite side / hypotenuse

1/2 = 8/h
h = 16

2)6/12 = 1/2
1/2 = sin 45°

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7 0
3 years ago
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Masja [62]
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3 0
3 years ago
The systolic blood pressure of adults in the USA is nearly normally distributed with a mean of 122 and standard deviation of 22
marin [14]

Answer: 4.27% of adults in the USA have stage 2 high blood pressure.

Step-by-step explanation:

Let x be a random variable that denotes a person with high blood pressure .

Given: Average blood pressure: \mu=122

Standard deviation: \sigma=22

Someone qualifies as having Stage 2 high blood pressure if their systolic blood pressure is 160 or higher.

The probability that an adult in the USA have stage 2 high blood pressure:

P(x\geq160)=P(\dfrac{x-\mu}{\sigma}}\geq\dfrac{160-122}{22})\\\\=P(z\geq1.72)\ \ \ [z=\dfrac{x-\mu}{\sigma}]\\\\=1-P(z

Hence, 4.27% of adults in the USA have stage 2 high blood pressure.

6 0
3 years ago
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