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bogdanovich [222]
3 years ago
8

- LT2XO 3) (5y2 – 2xy + 6x² – 3x + 7y - 9) + (3x² - 4x + 5) – (5y2 – 3y +6)

Mathematics
1 answer:
Anestetic [448]3 years ago
8 0

Answer:

(1, -1)

Step-by-step explanation:

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3 years ago
6x+4y=42 -3x+3y=-6 by elimination
creativ13 [48]

Answer:

x=5, y=2

Step-by-step explanation:

To solve this system, we need to find x and y. First, let's find x. In the first equation (6x+4y=42), subtract 4y on both sides to isolate 6x. This will result in 6x=42-4y. Divide by 6 on both sides to isolate x and get x=7-\frac{2}{3}y. Now we know what x equals. Go to the second equation ad plug this into it. So instead of -3x+3y=-6, you'll have -3(7-\frac{2}{3}y)+3y=-6. Use the distributive property to get -21+2y+3y=-6. Add 2y and 3y to get -21+5y=-6. Add 21 to both sides to isolate 5y and get 5y=15. Divide by 5 on both sides to isolate y and get y=3. Now that we know that y=3, we can plug this back into the equation that was bolded above so that we can find x, so we'll have x=7-\frac{2}{3}(3) since y=3, and we'll get x=7-\frac{6}{3}, or x=7-2, or x=5.

x=5

y=2

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