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Kruka [31]
2 years ago
10

HELP ASAP ILL MAKE YOU THE BRAINIEST find the value of c

Mathematics
1 answer:
STALIN [3.7K]2 years ago
7 0
<h3>Answer:  16.2364298 approximately</h3>

Work Shown:

tan(angle) = opposite/adjacent

tan(61) = x/9

x = 9*tan(61)

x = 16.2364298 approximately

Your calculator needs to be in degree mode. One quick way to check is to type in something like tan(45) and the result should be 1.

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What is the solution to the equation<br> 1/2x+3 = 2/3+1?
Alex

Answer:

x = -8/3

Step-by-step explanation:

1/2x+3 = 2/3+1

Combine like terms

1/2x+3 = 2/3 + 3/3

1/2x + 3 = 5/3

Subtract 3 from each side

1/2x + 3-3 = 5/3 - 3

1/2x = 5/3 - 9/3

1/2x = -4/3

Multiply each side by 2

1/2x *2 = -4/3*2

x = -8/3

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3 years ago
Determine if the triangles are congruent. If they are, state why.
Svet_ta [14]
Hi I just need points jeje
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2 years ago
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If point F is the midpoint of segment DE, which statement is true?
FinnZ [79.3K]
Segment DF is 1/2 the length of Segment DE. Since the entire segment is DE and it's midpoint is at F, the segment would be broken into 2 equal segments in one. Segment DF and FE. Segment DF is congruent to Segment FE.
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3 years ago
What is the formula of the area of any triangle
MrRissso [65]

Answer:Side x side x side

Step-by-step explanation:

Since it is usually equally sided, it would be SxSxS

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2 years ago
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The probability that an egg on a production line is cracked is 0.01. Two eggs are selected at random from the production line. F
musickatia [10]

Answer:

P(X \geq 1)=1-P(X

P(X=0)=(2C0)(0.01)^0 (1-0.01)^{2-0}=0.9801

And replacing we got:

P(X \geq 1) = 1-0.9801 = 0.0199

Step-by-step explanation:

Let X the random variable of interest "number of craked eggs", on this case we now that:

X \sim Binom(n=2, p=0.01)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

And we want to find this probability:

P(x \geq 1)=1-P(X

And we can find the probability:

P(X=0)=(2C0)(0.01)^0 (1-0.01)^{2-0}=0.9801

And replacing we got:

P(X \geq 1) = 1-0.9801 = 0.0199

5 0
2 years ago
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