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34kurt
2 years ago
11

Anyone have an old ps5 box; I’m pranking a friend??

Mathematics
2 answers:
Anna007 [38]2 years ago
8 0
No, I hope you find one for the prank tho lol XD
Amanda [17]2 years ago
5 0

Answer:

i do not :(

Step-by-step explanation:

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4 hours worked for $12; 7 hours worked for $28l
777dan777 [17]

Answer:

$293.00

Step-by-step explanation:

5 0
3 years ago
What is the percent of decrease from 10 to 5? Write your answer using a percent sign (%). WILL MARK BRAINLIEST!!! (I have to hav
vichka [17]

Answer:

50%

Step-by-step explanation:

the percent of decrease from 10 to 5 is 50%

When 10 is decreased to 5:

10-5= 5

5 is half of 10.

1/2 as a percent is 50%

5 0
3 years ago
Read 2 more answers
Could someone help me, please?
k0ka [10]

We can rewrite the expression under the radical as

\dfrac{81}{16}a^8b^{12}c^{16}=\left(\dfrac32a^2b^3c^4\right)^4

then taking the fourth root, we get

\sqrt[4]{\left(\dfrac32a^2b^3c^4\right)^4}=\left|\dfrac32a^2b^3c^4\right|

Why the absolute value? It's for the same reason that

\sqrt{x^2}=|x|

since both (-x)^2 and x^2 return the same number x^2, and |x| captures both possibilities. From here, we have

\left|\dfrac32a^2b^3c^4\right|=\left|\dfrac32\right|\left|a^2\right|\left|b^3\right|\left|c^4\right|

The absolute values disappear on all but the b term because all of \dfrac32, a^2 and c^4 are positive, while b^3 could potentially be negative. So we end up with

\dfrac32a^2\left|b^3\right|c^4=\dfrac32a^2|b|^3c^4

3 0
3 years ago
Find the perimeter of a triangle with sides lengths 8, 10, and 12.
shtirl [24]

Answer:

30

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Find the sample space for the experiment.
Bingel [31]

Answer:

The sample space is:

AB,\ AC,\ AD,\ AE,\\BC,\ BD,\ BE\\CD,\ CE\\DE

Step-by-step explanation:

The sample space of an experiment is a set of all the possible values that satisfies that experiment.

The five supervisors are A, B, C, D and E.

Two are to selected.

The number of ways to select 2 supervisors  from 5 is: {5\choose 2}=\frac{5!}{2!(5-2)!} =\frac{5!}{2!\times 3!}  = 10

The sample space will consist of 10 combinations.

The sample space is:

AB,\ AC,\ AD,\ AE,\\BC,\ BD,\ BE\\CD,\ CE\\DE

5 0
3 years ago
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