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ser-zykov [4K]
2 years ago
11

10.What is the acceleration of a freely falling object 5 seconds after it has been released from a height of 200 m

Physics
1 answer:
dybincka [34]2 years ago
6 0

Answer:

9.81 m/s^2

Explanation:

Acceleration is constant   9.81 m/s^2    ( of course....ignoring air friction)

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Which of the following statements CANNOT be supported by Kepler's laws of planetary motion?
horsena [70]

Answer:

B) A planet's speed as it moves around the sun will not be the same in six months.

Explanation:

A planet's speed as it moves around the sun will not be the same in six months, is a  statement that CANNOT be supported by Kepler's laws of planetary motion.

8 0
3 years ago
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If you move 50 meters in 10 seconds, what is your speed ​
iogann1982 [59]

Explanation:

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8 0
3 years ago
When will heat transfer within a liquid stop? (25 points)
exis [7]
Choice C.
That's when convection stops.
3 0
3 years ago
What derived unit is used to measure the slope of the line in this graph?
Alexxx [7]

Answer:

g/cm³

Explanation:

From the question given above,

The y-axis is representing mass (g)

The x-axis is representing volume (cm³)

Unit of slope =?

Slope of a graph is simply defined as the change in y-axis divided by the change in x-axis. Mathematically it is expressed as:

Slope = change in y-axis (Δy)/change in x-axis (Δx)

Slope = Δy/Δx

Thus, with the above formula, we can obtain the unit used for measuring the slope as follow:

y-axis = mass (g)

x-axis = volume (cm³)

Slope =.?

Slope = Δy/Δx

Slope = mass (g) /volume (cm³)

Slope = g/cm³

Therefore, the derive unit used for measuring the slope is g/cm³

5 0
3 years ago
A nature photographer is using a camera that has a lens with a focal length of 3.06 cm. The photographer is taking pictures of a
sleet_krkn [62]

Answer:

film is at distance of 3.07 cm from lens

Explanation:

Given data

focal length = 3.06 cm

distance = 10.4 m = 1040 cm

to find out

How far must the lens

solution

we apply here lens formula that is

1/f = 1/p + 1/q

here f = 3.06 and p = 1040 so we find q

1/f = 1/p + 1/q

1/3.06 = 1/1040 + 1/q

1/ q =  0.3258

q = 3.0690 cm

so film is at distance of 3.07 cm from lens

6 0
4 years ago
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