Ask question

Ask question

All categories

4 years ago

12

how much work must be done to accelerate an 8.5×10^5 kg train from a) 10m/s to 15m/s b) 15m/s to 20m/s and c) to an Initial stop

of 20m/s

1 answer:

boyakko [2]4 years ago

7 0

W = ΔE = 1/2 m (v₂ - v₁)²

W work
E kinetic energy
m mass
v₂ final velocity
v₁ initial velocity

You might be interested in

A hydraulic press has one piston of diameter 2.0 cm and the other piston of diameter 16.0 cm. What force must be applied to the

SVETLANKA909090 [29]

Answer:

<em>The force applied to the smaller piston = 2512 N</em>

Explanation:

Hydraulic press: A hydraulic press is a device used to produce a very large force. A hydraulic force operates based on pascal's principle.

F/f = A/a................ Equation 1

making f the subject of the equation above

f =(F×a)/A............. Equation 2

Where F = Force on the larger piston, f = force on the smaller piston, A = area of the larger piston, a = area of the smaller piston.

<em>Given: F = 3200 N, and</em>

<em>Area (A) = πD²/4 where D = 16.0 cm = 0.16 m</em>

<em>A = 3.143×(0.16)²/4 = 0.02 m²</em>

<em>Also</em>

<em>a = πd²/4 where d = 2 cm = 0.02 cm</em>

<em>a = 3.143×(0.02)²/4</em>

<em>a = 0.0157 m²</em>

<em>Substituting these values into equation 2</em>

<em>f = (3200×0.0157)/0.02</em>

<em>f = 2512 N</em>

<em>The force applied to the smaller piston = 2512 N</em>

5 0

3 years ago

A garden hose having with an internal diameter of 1.1 cm is connected to a (stationary) lawn sprinkler that consists merely of a

trapecia [35]

Answer:

Water leaves the sprinkler at a speed of 2.322 m/sec

Explanation:

We have given internal diameter of the garden $d_1=1.1cm$

Speed of water in the hose is $v_1=0.95m/sec$

Number of holes n = 22

Diameter of each holes $d_2=15cm$

According to continuity equation $A_1v_1=A_2v_2$

$d_1^2\times v_1=22\times d_2^2v_2$

$1.1^2\times 0.95=22\times 0.15^2\times v_2$

$v_2=2.322m/sec$

So water leaves the sprinkler at a speed of 2.322 m/sec

6 0

3 years ago

A gun is fired with angle of elevation 30°. What is the muzzle speed if the maximum height of the shell is 544 m? (Round your an

Artemon [7]

Answer:

206.62313 m/s

Explanation:

u = Muzzle speed

g = Acceleration due to gravity = 9.8 m/s²

$\theta$ = Angle at which the bullet is fired = 30°

h = Maximum height = 544 m

Maximum height is given by

$h=\dfrac{u^2sin^2\theta}{2g}\\\Rightarrow u=\sqrt{\dfrac{2gh}{sin^2\theta}}\\\Rightarrow u=\sqrt{\dfrac{2\times 9.81\times 544}{sin^2(30)}}\\\Rightarrow u=206.62313\ m/s$

The muzzle speed is 206.62313 m/s

6 0

4 years ago

If you gonna answer give all the answers :-)

bearhunter [10]

I say 1 it seems the most accurate

7 0

3 years ago

Compare contrast atoms and molecules

creativ13 [48]

Atoms are a single entity (one type of element) whereas a molecule is a group of 2 or more atoms chemically bonded. Don't be confused that atoms are a single particle because they can be split into protons, neutrons and electrons.

5 0

3 years ago