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skad [1K]
3 years ago
9

The maximum gauge pressure in a hydraulic lift is 18.0 atm what is the largest size vehicle

Physics
1 answer:
victus00 [196]3 years ago
3 0
There is a missing part in the question. Found the complete text on internet:
"<span>What is the largest size vehicle (kg) it can lift if the diameter of the output line is 28.0 cm? "

Solution
The diameter of the piston is 28.0 cm, this means its radius is 14.0 cm (half the diameter), so the area of the piston is
</span>A=\pi r^2 = \pi (0.14 m)^2 =6.15 \cdot 10^{-2} m^2
<span>
The maximum pressure of the lift is
</span>p=18.0 atm = 1.82 \cdot 10^6 Pa
<span>
Therefore the maximum force the piston can lift is
</span>F=pA=(1.82 \cdot 10^6 Pa)(6.15 \cdot 10^{-2} m^2)=1.12 \cdot 10^5 N
<span>
And the size (the mass) of the vehicle is
</span>m= \frac{F}{g}= \frac{1.12 \cdot 10^5 Pa}{9.81 m/s^2} =1.14 \cdot 10^4 kg<span>
</span>
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Answer:

8 seconds

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(b) 5610 Ns.

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Explanation:

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Mathematically, change in momentum is expressed as

ΔM = mΔv......................... Equation 1

Where ΔM = change in momentum, m = mass of snowmobile, Δv = change in velocity.

Given: m = 330 kg, Δv = v₂-v₁ = 23-6 = 17 m/s.

Note: v₁ and v₂ are the initial and the final velocity of the snowmobile.

ΔM = 330(17)

ΔM = 5610 kgm/s.

(b) Impulse: This can be defined as the product and force and time. The S.I unit of impulse is Ns.

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I = ΔM................ Equation 2

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Since ΔM = 5610 kgm/s.

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I = 5610 Ns.

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(c) Force: This can be defined as the product of the mass of a body and its acceleration. The S.I unit of force is Newton (N).

F = ma ................................. Equation 3

F = force, m = mass of the body, a = acceleration

But,

a = ( v₂-v₁)/t

Where v₂ = 23.0 m/s, v₁ = 6.0 m/s t = 60.0 s.

a = (23-6)/60

a = 0.283 m/s².

Substituting the value a and m into equation 3

F = 330(0.2383)

F = 78.639 N.

F ≈ 78. 64 N

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