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BabaBlast [244]
3 years ago
13

Please hurry no links

Mathematics
2 answers:
Alja [10]3 years ago
8 0
The answer is the third one (5/2)
mr Goodwill [35]3 years ago
4 0

Answer:

its c

Step-by-step explanation:

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PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!!!!!!!!!!!!!!!!!!!PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!
snow_lady [41]
A= pi x r^2 x h
so pi x 16 x5

A= 80 pi or 251.3
5 0
3 years ago
Two streets bounding your triangular lot make an angle of 74∘. The lengths of the two sides of the lot on these streets are 126
ycow [4]

Answer: a) Yes, there is enough fance

b) 58.1° and 47.9°

c) The city will not approve, because 1/3 of the area is just 2220.5ft²

Step-by-step explanation:

a) using law of cosines: x is the side we do not know.

x² = 126² + 110² - 2.126.110.cos74°

x² = 20335.3

x = 142.6 ft

So 150 > 142.6, there is enough fance

b) using law of sine:

sin 74/ 142.6 = sinα/126 = sinβ/110

sin 74/ 142.6 = sinα/126

0.006741 = sinα/126

sinα = 0.849

α = sin⁻¹(0.849)

α = 58.1°

sin 74/ 142.6 = sinβ/110

sin 74/ 142.6 = sinβ/110

0.006741 = sinβ/110

sinβ = 0.741

β = sin⁻¹(0.741)

β = 47.9°

Checking: 74+58.1+47.9 = 180° ok

c) Using Heron A² = p(p-a)(p-b)(p-c)

p = a+b+c/2

p=126+110+142.6/2

p=189.3

A² = 189.3(189.3-126)(189.3-110)(189.3-142.6)

A = 6661.5 ft²

1/3 A = 2220.5

So 2300 >  2220.5. The area you want to build is bigger than the area available.

The city will not approve

7 0
3 years ago
The coordinates of the vertices of a rectangle are (−3, 4) , (7, 2) , (6, −3) , and (−4, −1) . What is the perimeter of the rect
ki77a [65]

Answrer

Find out the what is the perimeter of the rectangle .

To prove

Now as shown in the figure.

Name the coordinates as.

A(−3, 4) ,B (7, 2) , C(6, −3) , and D(−4, −1) .

In rectangle opposite sides are equal.

Thus

AB = DC

AD = BC

Formula

Disatnce\ formula = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2}}

Now the points  A(−3, 4) and  B(7, 2)

AB = \sqrt{(7- (-3))^{2} +(2- 4)^{2}}

AB = \sqrt{(10)^{2} +(-2)^{2}}

AB = \sqrt{100+4}

AB = \sqrt{104}

AB = 2\sqrt{26}\units

Thus

CD= 2\sqrt{26}\units

Now the points

A (−3, 4) , D (−4, −1)

AD = \sqrt{(-4 - (-3))^{2} +(-1- 4)^{2}}

AD = \sqrt{(-1)^{2} +(-5)^{2}}

AD = \sqrt{1 + 25}

AD = \sqrt{26}\units

Thus

BC = \sqrt{26}\units  

Formula

Perimeter of rectangle = 2 (Length + Breadth)

Here

Length = 2\sqrt{26}\ units

Breadth = \sqrt{26}\ units  

Perimeter\ of\ rectangle = 2(2\sqrt{26} +\sqrt{26})

Perimeter\ of\ rectangle = 2(3\sqrt{26})

Perimeter\ of\ rectangle = 6\sqrt{26}

\sqrt{26} = 5.1 (Approx)

Perimeter\ of\ rectangle = 6\times 5.1

Perimeter of a rectangle = 30.6 units.

Therefore the perimeter of a rectangle is 30.6 units.

8 0
3 years ago
Use the piecewise function to evaluate points f(–1), f(2), and f(12).​
scoundrel [369]

Answer:

Step-by-step explanation:

f(- 1) = - 1 + 4 = 3

f(2) = 2 + 4 = 6

f(12) = 4(12) - 7 = 41

3 0
3 years ago
Read 2 more answers
Question on picture ​
Advocard [28]

Answer:

i dont know

hope you find the answer though

Step-by-step explanation:

4 0
3 years ago
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