35 has 4 divisors, hence two factor pairs: 1*35 and 5*7. Each corresponds to a set of perfect squares that differ by 35
One pair is ((35±1)/2)^2 = {17^2, 18^2} = {289, 324}
The other is ((7±5)/2)^2 = {1^2, 6^2} = {1, 36}
Answer: f(x) = 13
Step-by-step explanation:
When x = 10
f(10) = 10/2 + 8
= 5+8
= 13
Hope this helps!
Could you send a clear image from frobt view
The answer is one third or 1/3 multiply diagonal both ways and then multiply denominators
It would be 0.2
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